问题
Suppose I have the following code:
CompletableFuture<Integer> future
= CompletableFuture.supplyAsync( () -> 0);
thenApply
case:
future.thenApply( x -> x + 1 )
.thenApply( x -> x + 1 )
.thenAccept( x -> System.out.println(x));
Here the output will be 2. Now in case of thenApplyAsync
:
future.thenApplyAsync( x -> x + 1 ) // first step
.thenApplyAsync( x -> x + 1 ) // second step
.thenAccept( x -> System.out.println(x)); // third step
I read in this blog that each thenApplyAsync
are executed in a separate thread and 'at the same time'(that means following thenApplyAsyncs
started before preceding thenApplyAsyncs
finish), if so, what is the input argument value of the second step if the first step not finished?
Where will the result of the first step go if not taken by the second step? the third step will take which step's result?
If the second step has to wait for the result of the first step then what is the point of Async
?
Here x -> x + 1 is just to show the point, what I want know is in cases of very long computation.
回答1:
The difference has to do with the Executor
that is responsible for running the code. Each operator on CompletableFuture
generally has 3 versions.
thenApply(fn)
- runsfn
on a thread defined by theCompleteableFuture
on which it is called, so you generally cannot know where this will be executed. It might immediately execute if the result is already available.thenApplyAsync(fn)
- runsfn
on a environment-defined executor regardless of circumstances. ForCompletableFuture
this will generally beForkJoinPool.commonPool()
.thenApplyAsync(fn,exec)
- runsfn
onexec
.
In the end the result is the same, but the scheduling behavior depends on the choice of method.
回答2:
You're misunderstanding the examples you quoted. In both examples, the second function has to wait for the first function to complete. Whenever you call a.then___(b -> ...)
, input b
is the result of a
and has to wait for a
to complete, regardless of whether you use Async or not.
The actual example in the article is
CompletableFuture<String> receiver = CompletableFuture.supplyAsync(this::findReceiver);
receiver.thenApplyAsync(this::sendMsg);
receiver.thenApplyAsync(this::sendMsg);
Notice the thenApplyAsync
both applied on reciver
, not chained in the same statement. This means both function can start once receiver
completes, in an unspecified order. (Any assumption of order is implementation dependent.)
More technical explanation
I must point out that thenApply
and thenApplyAsync
are terribly named and are confusing to the unfamiliar. There is nothing in thenApplyAsync
that is more asynchronous than thenApply
from the contract of these methods.
The difference between the two has to do with on which thread the function is run. The function supplied to thenApply
may run on any of the threads that
- call
complete
- call
thenApply
on the same instance
while thenApplyAsync
either uses a default Executor
(a.k.a. thread pool), or a supplied Executor
.
Asynchrony != threads
thenApply
/thenApplyAsync
, and their counterparts thenCompose
/thenComposeAsync
, handle
/handleAsync
, thenAccept
/thenAcceptAsync
, are all asynchronous! The asynchronous part of these function has to do with the fact that an asynchronous operation eventually calls complete
or completeExceptionally
. The idea came from Javascript, which is indeed asynchronous but isn't multi-threaded.
回答3:
This is what the documentation says about CompletableFuture's
thenApplyAsync:
Returns a new CompletionStage that, when this stage completes normally, is executed using this stage's default asynchronous execution facility, with this stage's result as the argument to the supplied function.
So, thenApplyAsync
has to wait for the previous thenApplyAsync's
result:
In your case you first do the synchronous work and then the asynchronous one. So, it does not matter that the second one is asynchronous because it is started only after the synchrounous work has finished.
Let's switch it up. In some cases "async result: 2" will be printed first and in some cases "sync result: 2" will be printed first. Here it makes a difference because both call 1 and 2 can run asynchronously, call 1 on a separate thread and call 2 on some other thread, which might be the main thread.
CompletableFuture<Integer> future
= CompletableFuture.supplyAsync(() -> 0);
future.thenApplyAsync(x -> x + 1) // call 1
.thenApplyAsync(x -> x + 1)
.thenAccept(x -> System.out.println("async result: " + x));
future.thenApply(x -> x + 1) // call 2
.thenApply(x -> x + 1)
.thenAccept(x -> System.out.println("sync result:" + x));
回答4:
The second step (i.e. computation) will always be executed after the first step.
If the second step has to wait for the result of the first step then what is the point of Async?
Async means in this case that you are guaranteed that the method will return quickly and the computation will be executed in a different thread.
When calling thenApply
(without async), then you have no such guarantee. In this case the computation may be executed synchronously i.e. in the same thread that calls thenApply
if the CompletableFuture is already completed by the time the method is called. But the computation may also be executed asynchronously by the thread that completes the future or some other thread that calls a method on the same CompletableFuture
. This answer: https://stackoverflow.com/a/46062939/1235217 explained in detail what thenApply does and does not guarantee.
So when should you use thenApply
and when thenApplyAsync
? I use the following rule of thumb:
- non-async: only if the task is very small and non-blocking, because in this case we don't care which of the possible threads executes it
- async (often with an explicit executor as parameter): for all other tasks
来源:https://stackoverflow.com/questions/47489338/what-is-the-difference-between-thenapply-and-thenapplyasync-of-java-completablef