Conversion of Scala map containing Boolean to Java map containing java.lang.Boolean

女生的网名这么多〃 提交于 2019-12-03 05:58:30

While JavaConversions will convert the Scala Map to a java.util.Map, and Scala implicitly converts scala.Boolean to java.lang.Boolean, Scala won't perform two implicit conversions to get the type you want.

Boolean provides a box method for explicit conversion.

val b: java.util.Map[Int, java.lang.Boolean] = a.mapValues(Boolean.box)

If you're doing this frequently in your code, you can define your own implicit conversion for all Map[T, Boolean].

import scala.collection.JavaConversions._

implicit def boolMap2Java[T](m: Map[T, Boolean]): 
  java.util.Map[T, java.lang.Boolean] = m.mapValues(Boolean.box)

val b: java.util.Map[Int, java.lang.Boolean] = a

scala.collection.JavaConversions isn't going to help you with the scala.Boolean to java.lang.Boolean problem. The following will work, though, using the boolean2Boolean method from scala.Predef:

val a = Map[Int, Boolean](1 -> true, 2 -> false)
val b: java.util.Map[Int, java.lang.Boolean] = a.mapValues(boolean2Boolean)

Or you can use Java's Boolean(boolean value) constructor:

val a = Map[Int, Boolean](1 -> true, 2 -> false)
val b: java.util.Map[Int, java.lang.Boolean] = 
         a.mapValues(new java.lang.Boolean(_))

Or you can just declare the first map to use the Java reference type:

val a = Map[Int, java.lang.Boolean](1 -> true, 2 -> false)
val b: java.util.Map[Int, java.lang.Boolean] = a
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