Counting number of children in hierarchical SQL data

喜你入骨 提交于 2019-12-03 05:42:43

Using a CTE would get you what you want.

  • Recursively go through all children, remembering the root.
  • COUNT the items for each root.
  • JOIN these again with your original table to produce the results.

Test Data

DECLARE @Data TABLE (
  ID INTEGER PRIMARY KEY
  , ParentID INTEGER
  , Text VARCHAR(32)
  , Price INTEGER
)

INSERT INTO @Data
  SELECT 1, Null, 'Root', NULL
  UNION ALL SELECT 2, 1, 'Flowers', NULL
  UNION ALL SELECT 3, 1, 'Electro', NULL
  UNION ALL SELECT 4, 2, 'Rose', 10
  UNION ALL SELECT 5, 2, 'Violet', 5
  UNION ALL SELECT 6, 4, 'Red Rose', 12
  UNION ALL SELECT 7, 3, 'Television', 100
  UNION ALL SELECT 8, 3, 'Radio', 70
  UNION ALL SELECT 9, 8, 'Webradio', 90

SQL Statement

;WITH ChildrenCTE AS (
  SELECT  RootID = ID, ID
  FROM    @Data
  UNION ALL
  SELECT  cte.RootID, d.ID
  FROM    ChildrenCTE cte
          INNER JOIN @Data d ON d.ParentID = cte.ID
)
SELECT  d.ID, d.ParentID, d.Text, d.Price, cnt.Children
FROM    @Data d
        INNER JOIN (
          SELECT  ID = RootID, Children = COUNT(*) - 1
          FROM    ChildrenCTE
          GROUP BY RootID
        ) cnt ON cnt.ID = d.ID

Consider using a modified preorder tree traversal way of storing the hierarchical data. See http://www.sitepoint.com/hierarchical-data-database/

Determining number of children for any node then becomes a simple:

SELECT (right-left-1) / 2 AS num_children FROM ...
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