Enumerate NSDictionary with keys and objects, PHP style

落爺英雄遲暮 提交于 2019-12-03 05:18:05

Perhaps look into NSDictionary's method:

enumerateKeysAndObjectsUsingBlock:(void (^)(id key, id obj, BOOL *stop))

If you're not familiar with blocks in C/Objective-C, this is a good tutorial: http://thirdcog.eu/pwcblocks/

NSDictionary* d = [NSDictionary dictionaryWithObjectsAndKeys:@"obj1",@"key1",
                                                           @"obj2",@"key2",
                                                           @"obj3",@"key3",
                                                           @"obj4",@"key4",nil];

for (id key in [d allKeys]) {
    NSLog(@"%@ - %@",key,[d objectForKey:key]);
}

Outputs:

keytest[7880:a0f] key3 - obj3
keytest[7880:a0f] key1 - obj1
keytest[7880:a0f] key4 - obj4
keytest[7880:a0f] key2 - obj2

Now much easier:

for (NSString * key in dict)
{
    id/* or your type */ value = dict[key];
    ...
}
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!