How to generate n-grams in scala?

筅森魡賤 提交于 2019-12-03 03:18:37

Your questions could be a little more specific but here is my try.

val words = "the bee is the bee of the bees"
words.split(' ').sliding(2).foreach( p => println(p.mkString))

You may try this with a parameter of n

val words = "the bee is the bee of the bees"
val w = words.split(" ")

val n = 4
val ngrams = (for( i <- 1 to n) yield w.sliding(i).map(p => p.toList)).flatMap(x => x)
ngrams foreach println

List(the)
List(bee)
List(is)
List(the)
List(bee)
List(of)
List(the)
List(bees)
List(the, bee)
List(bee, is)
List(is, the)
List(the, bee)
List(bee, of)
List(of, the)
List(the, bees)
List(the, bee, is)
List(bee, is, the)
List(is, the, bee)
List(the, bee, of)
List(bee, of, the)
List(of, the, bees)
List(the, bee, is, the)
List(bee, is, the, bee)
List(is, the, bee, of)
List(the, bee, of, the)
List(bee, of, the, bees)

Here is a stream based approach. This will not required too much memory while computing n-grams.

object ngramstream extends App {

  def process(st: Stream[Array[String]])(f: Array[String] => Unit): Stream[Array[String]] = st match {
    case x #:: xs => {
      f(x)
      process(xs)(f)
    }
    case _ => Stream[Array[String]]()
  }

  def ngrams(n: Int, words: Array[String]) = {
    // exclude 1-grams
    (2 to n).map { i => words.sliding(i).toStream }
      .foldLeft(Stream[Array[String]]()) {
        (a, b) => a #::: b
      }
  }

  val words = "the bee is the bee of the bees"
  val n = 4
  val ngrams2 = ngrams(n, words.split(" "))

  process(ngrams2) { x =>
    println(x.toList)
  }

}

OUTPUT:

List(the, bee)
List(bee, is)
List(is, the)
List(the, bee)
List(bee, of)
List(of, the)
List(the, bees)
List(the, bee, is)
List(bee, is, the)
List(is, the, bee)
List(the, bee, of)
List(bee, of, the)
List(of, the, bees)
List(the, bee, is, the)
List(bee, is, the, bee)
List(is, the, bee, of)
List(the, bee, of, the)
List(bee, of, the, bees)
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