How do I exclude Weekend days in a SQL Server query?

风流意气都作罢 提交于 2019-11-26 17:25:49

When dealing with day-of-week calculations, it's important to take account of the current DATEFIRST settings. This query will always correctly exclude weekend days, using @@DATEFIRST to account for any possible setting for the first day of the week.

SELECT *
FROM your_table
WHERE ((DATEPART(dw, date_created) + @@DATEFIRST) % 7) NOT IN (0, 1)
SELECT date_created
FROM your_table
WHERE DATENAME(dw, date_created) NOT IN ('Saturday', 'Sunday')

Assuming you're using SQL Server, use DATEPART with dw:

SELECT date_created
FROM your_table
WHERE DATEPART(dw, date_created) NOT IN (1, 7);

EDIT: I should point out that the actual numeric value returned by DATEPART(dw) is determined by the value set by using SET DATEFIRST:
http://msdn.microsoft.com/en-us/library/ms181598.aspx

Try the DATENAME() function:

select [date_created]
from table
where DATENAME(WEEKDAY, [date_created]) <> 'Saturday'
  and DATENAME(WEEKDAY, [date_created]) <> 'Sunday'

The answer depends on your server's week-start set up, so it's either

SELECT [date_created] FROM table WHERE DATEPART(w,[date_created]) NOT IN (7,1)

if Sunday is the first day of the week for your server

or

SELECT [date_created] FROM table WHERE DATEPART(w,[date_created]) NOT IN (6,7)

if Monday is the first day of the week for your server

Comment if you've got any questions :-)

Sarabpreet Singh Anand

Calculate Leave working days in a table column as a default value--updated

If you are using SQL here is the query which can help you: http://gallery.technet.microsoft.com/Calculate...

Try this code

select (DATEDIFF(DD,'2014-08-01','2014-08-14')+1)- (DATEDIFF(WK,'2014-08-01','2014-08-14')* 2)
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