passing const pointer by reference

北战南征 提交于 2019-12-03 02:29:17

Because it isn't type-safe. Consider:

const float f = 2.0;
int foo(const float* &a) {
    a = &f;
    return 0;
}
int main() {
    float* a;
    foo(a);
    *a = 7.0;

    return 0;
}

Any non-const reference or pointer must necessarily be invariant in the pointed-to type, because a non-const pointer or reference supports reading (a covariant operation) and also writing (a contravariant operation).

const must be added from the greatest indirection level first. This would work:

int foo(float* const &a) {
    return 0;
}
int main() {
    float* a;
    foo(a);

    return 0;
}
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