I'm trying to serialize a pointer to a polymorphic class Shape
. So I need to use the BOOST_CLASS_EXPORT
macro to define a GUID for each subclass. The problem: where to put it?
Let me show a minimal test case first:
shapes.hpp
#include <boost/serialization/access.hpp>
#include <boost/serialization/base_object.hpp>
#include <boost/serialization/export.hpp>
class Shape {
friend class boost::serialization::access;
template<typename Archive>
void serialize(Archive &ar, unsigned int const version) {
// nothing to do
}
public:
virtual ~Shape() { }
};
class Rect : public Shape {
friend class boost::serialization::access;
template<typename Archive>
void serialize(Archive &ar, unsigned int const version) {
ar & boost::serialization::base_object<Shape>(*this);
}
public:
virtual ~Rect() { }
};
#ifdef EXPORT_IN_HEADER
BOOST_CLASS_EXPORT(Rect)
#endif
export.cpp
#include <boost/serialization/export.hpp>
#include "shapes.hpp"
#ifdef EXPORT_IN_OBJECT
BOOST_CLASS_EXPORT(Rect)
#endif
main.cpp
#include <iostream>
#include <boost/archive/text_oarchive.hpp>
#include <boost/serialization/export.hpp>
#include "shapes.hpp"
#ifdef EXPORT_IN_MAIN
BOOST_CLASS_EXPORT(Rect)
#endif
int main() {
Shape *shape = new Rect();
boost::archive::text_oarchive ar(std::cout);
ar << shape;
}
On gcc, I compile these with
g++ -omain main.cpp export.cpp -Wl,-Bstatic -lboost_serialization-mt -Wl,-Bdynamic -DEXPORT_IN_XXX
Here, export.cpp
may look a bit silly. In my actual situation, it contains an enclosing class that uses the PIMPL idiom, and tries to serialize its (polymorphic) Shape
implementation. The important point is: the BOOST_CLASS_EXPORT
could be in a different object file than the code that invokes the serialization.
So here's the problem: where to use BOOST_CLASS_EXPORT
? I have three options, which can be enabled using the EXPORT_IN_XXX
macros.
EXPORT_IN_MAIN
works, but is not what I want. The code invoking the serialization should not need to know about the implementation details of the PIMPL class.EXPORT_IN_OBJECT
compiles, but does not work: it results in aboost::archive::archive_exception
with the messageunregistered void cast
. According to the documentation, this should be solved by serializing base classes usingboost::serialization::base_object
, like I did, but it doesn't help.EXPORT_IN_HEADER
does not even compile. The macroBOOST_CLASS_EXPORT
expands to a template specialization (which we'd like to be in the header file), but also to the definitiof of a static member therein. So I get a linker error about amultiple definition of 'boost::archive::detail::init_guid<Rect>::guid_initializer'
.
If it matters, I'm using g++ 4.4.3 and Boost 1.40.
Exporting Class Serialization of the Boost.Serialization docs (1.44.0) states the following:
BOOST_CLASS_EXPORT
in the same source module that includes any of the archive class headers will instantiate code [...]Note that the implemenation of this functionality requires that the
BOOST_CLASS_EXPORT
macro appear after and the inclusion of any archive class headers for which code is to be instantiated. So, code that usesBOOST_CLASS_EXPORT
will look like the following:
#include <boost/archive/text_oarchive.hpp>
#include <boost/archive/text_oarchive.hpp>
... // other archives
#include "a.hpp" // header declaration for class a
BOOST_CLASS_EXPORT(a)
... // other class headers and exports
[...] Including
BOOST_CLASS_EXPORT
in the "a.hpp" header itself as one would do with other serialization traits will make it difficult or impossible to follow the rule above regarding inclusion of archive headers beforeBOOST_CLASS_EXPORT
is invoked. This can best be addressed by usingBOOST_CLASS_EXPORT_KEY
in the header declarations andBOOST_CLASS_EXPORT_IMPLEMENT
in the class definition file.
I ended up putting all the serialization code in a header s11n.h
that is included from the CPP file that invokes the serialization. Essentially, the EXPORT_IN_MAIN
scenario I sketched above, but with the BOOST_CLASS_EXPORT
macro invocations in a different file.
This only works as long as only one compilation unit includes s11n.h
, of course, so although it works for now, it's no real solution...
You can use EXPORT_IN_OBJECT but the file that contains BOOST_CLASS_EXPORT must also include all the archive hpp files that plan to use.
This is because the BOOST_CLASS_EXPORT macro registers the derived type information which each archive it thinks you will use (implicitly determined based upon which archives you have included.)
In your example, use EXPORT_IN_OBJECT but also add #include to export.cpp.
In our code, we created archives.hpp that contains the archives we use and include it where ever we need to use BOOST_CLASS_EXPORT. (That way we have a single official list of archives.)
The downside is that we need to rebuild everything when we decide to use a new archive type, but we found that much easier to use than the polymorphic archive support.
Check out this older thread.
you can use and unique BOOST_CLASS_EXPORT_GUID() for each .cpp and add it only in the .cpp. not the .h
This problem drove me insane until I realized that my base class was not polymorphic. In other words, it never used the keyword "virtual" anywhere. Because I didn't need polymorphic behavior.
Here is how I fixed it:
- I just slapped the keyword "virtual" on some random method in my base class.
In my derived class's .cpp file, I added the following:
#include <boost/serialization/export.hpp> BOOST_CLASS_EXPORT(testnamespace::derivedclass)
This is all that I had to do.
来源:https://stackoverflow.com/questions/3396330/where-to-put-boost-class-export-for-boostserialization