问题
I want to check if a variable has a number in it, I just want to see if there is one I don't care if it has any thing else in it like so:
"abc" - false
"!./#()" - false
"!./#()abc" - false
"123" - true
"abc123" - true
"!./#()123" - true
"abc !./#() 123" -true
There are easy ways of doing this if you want to know that is all numbers but not if it just has one. Thanks for your help.
回答1:
You can use the strcspn function:
if (strcspn($_REQUEST['q'], '0123456789') != strlen($_REQUEST['q']))
echo "true";
else
echo "false";
strcspn
returns the length of the part that does not contain any integers. We compare that with the string length, and if they differ, then there must have been an integer.
There is no need to invoke the regular expression engine for this.
回答2:
$result = preg_match("/\\d/", $yourString) > 0;
回答3:
Holding on to spirit of @Martin, I found a another function that works in similar fashion.
(strpbrk($var, '0123456789')
e.g. test case
<?php
function a($var) {
return (strcspn($var, '0123456789') != strlen($var));
}
function b($var) {
return (strpbrk($var, '0123456789'));
}
$var = array("abc", "!./#()", "!./#()abc", "123", "abc123", "!./#()123", "abc !./#() 123");
foreach ($var as $v) {
echo $v . ' = ' . b($v) .'<hr />';
}
?>
回答4:
This should help you:
$numberOfNumbersFound = preg_match("/[0-9]+/", $yourString);
You could get more out of the preg_match function, so have a look at its manual
回答5:
you can use this pattern to test your string using regular expressions:
$isNumeric = preg_match("/\S*\d+\S*/", $string) ? true : false;
来源:https://stackoverflow.com/questions/901708/check-if-variable-has-a-number-php