jQuery delay() - how to stop it?

问题

I already tried stop(true,true), stop(true) and clearQueue(); but this doesn't work.

I have problem with fast changing slides, i already have some function what have to reset everything, but it doesn't work.

function reset(){
   $('div').clearQueue();
   $('#img').html('').css({'left':0,'right':0,'opacity':1,'z-index':1});
   $('#img2').html('').css({'left':0,'right':0,'opacity':1,'z-index':1});
   $('#place').html('');$('#place').html('<div id="img"></div><div id="img2"></div>');
}

But i thing this doesn't stop (or delete) delay() function on animations. So I don't know if i don't have to use setTimeout function.

Here is piece of animation script:

reset();
actual_slide=2;
  $('#img').html('<img src="'+image[4]+'" alt="Obrázek">').css({'opacity':0,'z-index':2}).delay(time_delay/5).fadeTo(time_fast,1).delay(time_delay*2).fadeTo(time_fast,0);
  $('#img2').html('<img src="'+image[3]+'" alt="Obrázek">').css({'opacity':'0','top':0}).fadeTo(time_fast,1).animate({'top':'-495'},time_delay*3,function(){
    if(actual_slide==2){$('#img2').css({'top':0}).fadeTo(time_fast*2,0).html('');}else{reset();}
    if(actual_slide==2){$('#img').html('<img src="'+image[3]+'" id="1" alt="Obrázek">').fadeTo(time_fast*2,'1').css({'left':-300,'top':-700}).animate({'left':-900,'top':-700},time_delay*2);}else{reset();}
    if(actual_slide==2){$('#1').css({'width':1365,'height':1200}).animate({'width':1665,'height':1400},time_delay*2);}else{reset();}
  });                          

That actual_slide have to protect it before repeating that function, but that doesn't work too.. Problem is when i fast changing slides, because that reset doesn't stop everything, and it start doing things what i don't want to have in (like change picture to other and other).

回答1:

From the jQuery delay page:

The .delay() method is best for delaying between queued jQuery effects. Because it is limited—it doesn't, for example, offer a way to cancel the delay—.delay() is not a replacement for JavaScript's native setTimeout function, which may be more appropriate for certain use cases.

Take a look at the doTimeout plugin; it may be what you are looking for.

I hope this helps!

回答2:

You can break .delay() by .dequeue() function

here is example

//this is only for make sure that we skip 'delay', not other function
var inDelay = false;

function start()
{
    $('.gfx').animate
    ({
        width: 100
    }, function(){inDelay = true}).delay(3000).animate
    ({
        width: 0
    }, function(){inDelay = false})
}

function breakTheDelay()
{
    if(inDelay)
    {
        $('.gfx').dequeue();
    }
}

http://jsfiddle.net/wasikuss/5288z/

//edit: more complex example provided with logging timestamps and cleanup ( without cleanup, multiple clicks on Start is unpredictable ) to prove that it works

http://jsfiddle.net/q0058whc/

or below

//this is only for make sure that we skip 'delay', not other function
var inDelay = false;
var ltime = 0;

// console log will aways show 'end' values: 2000, 1000 an 400
// values may be different due to time wasted on calling functions
// sometimes delay is shorten by 0-200ms, it can be caused by js engine probably  

function start()
{
    cleanup();
    ltime = (1*new Date());
    $('.gfx').queue('fx', function(next)
    {
      logtime( 'animate1_start' );
    	$('.gfx').animate
      ({
          width: 100
      }, 2000, function(){logtime('animate1_end');inDelay = true;})
      next();
    })
    .queue('fx', function(next)
    {
    	logtime('delay_start');
    	next()
    })
    .delay(1000)
    .queue('fx', function(next)
    {
    	logtime('delay_end');
    	next()
    })
    .queue('fx', function(next)
    {
    	logtime('animate0_start');
    	$('.gfx').animate
      ({
          width: 0
      }, function(){logtime('animate0_end');inDelay = false;})
      next()
    });
}

function cleanup()
{
		// remove current queue
    $('.gfx').clearQueue()
    // first animate runned interval. stop it 
    .stop()
    // reset width of element
    .css('width',0)
}

function logtime( name )
{
	var ntime = (1*new Date());
	console.log( name + ': ' + ( ntime - ltime ) );
  ltime = ntime;
}

function breakTheDelay()
{
    if(inDelay)
    {
        $('.gfx').dequeue();
    }
}

//
// version without 'inDelay' check only if you know what are you doing
// http://jsfiddle.net/wasikuss/hkw9H/
//

.gfx
{
    background: red;
    width: 0;
    height: 10px
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<button onclick="start()">Start</button>
<button onclick="breakTheDelay()">Can't wait!</button>
<div class="gfx"></div>

回答3:

Via this post there's a very simple approach, which is to use .animate in place of .delay

回答4:

I wanted a user to rapidly restart an animation chain over and over again, sometimes in the middle of the animation. So instead of using delay() I animated to a bogus css propery {"null":1}. Here's a simple fade-in/fade-out. Seems to have worked for me!

//- fade in
$el.stop().animate({"opacity":1}, 200, "easeInSine", function(){
    //- delay for 2000ms
    $el.stop().animate({"null":1}, 2000, function(){
        //- fade out
        $el.stop().animate({"opacity":0}, 1000, "easeInOutSine", function(){
            //- final callback
        });
    });
});

来源：https://stackoverflow.com/questions/7929266/jquery-delay-how-to-stop-it