c++ for loop converted to a while loop

流过昼夜 提交于 2019-12-02 23:15:13

问题


Hi I wrote this code to print out factors of an integer with a for looop

how do i write it with a while loop?

for(int i = 1; i <  integer+1; i++)
{
    if(integer % i == 0)
        cout<< i<<" ";
}

回答1:


int i = 1;
while (i < integer+1)
{
  if(integer % i == 0)
    cout<< i<<" ";
  i++;
}

Or even better:

int i = 0;
while (++i < integer+1)
{
  if(integer % i == 0)
    cout<< i<<" ";
}



回答2:


int i = 1;
while(i < integer + 1) {
    // your current loop body goes here
    i++;
}

See equivalent forms of for loop.




回答3:


Following code will print the same result as your for loop in printing.

 int i = 1;
    while(i < integer + 1)
    {
        if(integer % i == 0)
         {   cout<< i<<" "; }
         i++;

    }


来源:https://stackoverflow.com/questions/9795898/c-for-loop-converted-to-a-while-loop

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