问题
I wrote the following code:
class Osoba{
private:
string imie, nazwisko, kolorOczu;
friend void Dziecko::coutall();
public:
Osoba(string imie, string nazwisko, string kolorOczu):imie(imie), nazwisko(nazwisko), kolorOczu(kolorOczu){};
void coutall(){
cout << "Imie: " << imie << endl; //
cout << "Nazwisko: " << nazwisko << endl;
cout << "Kolor oczu: " << kolorOczu << endl;
}
};
class Dziecko: public Osoba{
private:
string nazwaPrzedszkola, choroba;
typedef Osoba super;
public:
Dziecko(string imie, string nazwisko, string kolorOczu, string nazwaPrzedszkola, string choroba):super(imie, nazwisko, kolorOczu), nazwaPrzedszkola(nazwaPrzedszkola), choroba(choroba){};
void coutall(){
cout << super::imie; // this one gets underlined.
cout << "Nazwa przedszkola: " << nazwaPrzedszkola << endl;
cout << "Choroba: " << choroba << endl;
}
};
and this line is underlined:
cout << super::imie;
It says it's inaccessible. But in my opinion it is - I "friended" this method. I tried a forward declaration of class Dziecko - didn't work, either. What am I doing wrong?
回答1:
You cannot do it, because Dziecko::coutall is not defined when Osoba is compiled and there are no means in c++ to make forward member method declaration. Instead you can make friend all Dziecko class (as Nbr44 suggested)
回答2:
It seems you can't call that method because it uses private members of class Osoba
.
Try using the imie
as a protected variable instead of private.
Here is a short explenation.
The 2 options available are:
1) friend
the entire class, not a good practice when using inheritance.
2) Use protected members. this is the best way to access private members on inheritance.
来源:https://stackoverflow.com/questions/20954195/friend-methods-in-c-is-not-working