What happens when HashMap or HashSet maximum capacity is reached?

隐身守侯 提交于 2019-12-02 19:11:19

The underlying capacity of the array has to be a power of 2 (which is limited to 2^30) When this size is reached the load factor is effectively ignored and array stops growing.

At this point the rate of collisions increases.

Given the hashCode() only has 32-bits it wouldn't make sense to grow much big that this in any case.

/**
 * Rehashes the contents of this map into a new array with a
 * larger capacity.  This method is called automatically when the
 * number of keys in this map reaches its threshold.
 *
 * If current capacity is MAXIMUM_CAPACITY, this method does not
 * resize the map, but sets threshold to Integer.MAX_VALUE.
 * This has the effect of preventing future calls.
 *
 * @param newCapacity the new capacity, MUST be a power of two;
 *        must be greater than current capacity unless current
 *        capacity is MAXIMUM_CAPACITY (in which case value
 *        is irrelevant).
 */
void resize(int newCapacity) {
    Entry[] oldTable = table;
    int oldCapacity = oldTable.length;
    if (oldCapacity == MAXIMUM_CAPACITY) {
        threshold = Integer.MAX_VALUE;
        return;
    }

    Entry[] newTable = new Entry[newCapacity];
    transfer(newTable);
    table = newTable;
    threshold = (int)(newCapacity * loadFactor);
}

When the size exceeds Integer.MAX_VALUE it overflows.

void addEntry(int hash, K key, V value, int bucketIndex) {
Entry<K,V> e = table[bucketIndex];
    table[bucketIndex] = new Entry<K,V>(hash, key, value, e);
    if (size++ >= threshold)
        resize(2 * table.length);
}
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