Unzipping files in Python

Question

I read through the zipfile documentation, but couldn't understand how to unzip a file, only how to zip a file. How do I unzip all the contents of a zip file into the same directory?

Answer 1

import zipfile
with zipfile.ZipFile(path_to_zip_file, 'r') as zip_ref:
    zip_ref.extractall(directory_to_extract_to)

That's pretty much it!

Answer 2

If you are using Python 3.2 or later:

import zipfile
with zipfile.ZipFile("file.zip","r") as zip_ref:
    zip_ref.extractall("targetdir")

You dont need to use the close or try/catch with this as it uses the context manager construction.

Answer 3

Use the extractall method, if you're using Python 2.6+

zip = ZipFile('file.zip')
zip.extractall()

Answer 4

You can also import only ZipFile:

from zipfile import ZipFile
zf = ZipFile('path_to_file/file.zip', 'r')
zf.extractall('path_to_extract_folder')
zf.close()

Works in Python 2 and Python 3.

Answer 5

import os 
zip_file_path = "C:\AA\BB"
file_list = os.listdir(path)
abs_path = []
for a in file_list:
    x = zip_file_path+'\\'+a
    print x
    abs_path.append(x)
for f in abs_path:
    zip=zipfile.ZipFile(f)
    zip.extractall(zip_file_path)

This does not contain validation for the file if its not zip. If the folder contains non .zip file it will fail.

Answer 6

try this :

import zipfile
def un_zipFiles(path):
    files=os.listdir(path)
    for file in files:
        if file.endswith('.zip'):
            filePath=path+'/'+file
            zip_file = zipfile.ZipFile(filePath)
            for names in zip_file.namelist():
                zip_file.extract(names,path)
            zip_file.close() 

path : unzip file's path