Using sendmail from bash script for multiple recipients

Question

I'm running a bash script in cron to send mail to multiple recipients when a certain condition is met.

I've coded the variables like this:

subject="Subject"
from="user@domain.com"
recipients="user1@gmail.com user2@gmail.com"
mail="subject:$subject\nfrom:$from\nExample Message"

And the actual sending:

echo -e $mail | /usr/sbin/sendmail "$recipients"

The problem is that only user2@gmail.com is receiving the email. How can I change this so all the recipients receive the email?

NOTE: The solution has to be with sendmail, I'm using jailshell and it seems to be the only available method

Answer 1

Try doing this :

recipients="user1@gmail.com,user2@gmail.com,user3@gmail.com"

And another approach, using shell here-doc :

/usr/sbin/sendmail "$recipients" <<EOF
subject:$subject
from:$from

Example Message
EOF

Be sure to separate the headers from the body with a blank line as per RFC 822.

Answer 2

Use option -t for sendmail.

in your case - echo -e $mail | /usr/sbin/sendmail -t and add yout Recepient list to message itself like To: someone@somewhere.com someother@nowhere.com right after the line From:.....

-t option means - Read message for recipients. To:, Cc:, and Bcc: lines will be scanned for recipient addresses. The Bcc: line will be deleted before transmission.

Answer 3

to use sendmail from the shell script

subject="mail subject"
body="Hello World"
from="me@domain.com"
to="recipient1@domain.com,recipient2@domain.com"
echo -e "Subject:${subject}\n${body}" | sendmail -f "${from}" -t "${to}"