how to use the Box-Cox power transformation in R

I need to transform some data into a 'normal shape' and I read that Box-Cox can identify the exponent to use to transform the data.

For what I understood

car::boxCoxVariable(y)

is used for response variables in linear models, and

MASS::boxcox(object)

for a formula or fitted model object. So, because my data are the variable of a dataframe, the only function I found I could use is:

car::powerTransform(dataframe$variable, family="bcPower")

Is that correct? Or am I missing something?

The second question is about what to do after I obtain the

Estimated transformation parameters
dataframe$variable
0.6394806

Should I simply multiply the variable by this value? I did so:

aaa = 0.6394806
dataframe$variable2 = (dataframe$variable)*aaa

and then I run the shapiro-wilks test for normality, but again my data don't seem to follow a normal distribution:

shapiro.test(dataframe$variable2)
data:  dataframe$variable2
W = 0.97508, p-value < 2.2e-16

Box and Cox (1964) suggested a family of transformations designed to reduce nonnormality of the errors in a linear model. In turns out that in doing this, it often reduces non-linearity as well.

Here is a nice summary of the original work and all the work that's been done since: http://www.ime.usp.br/~abe/lista/pdfm9cJKUmFZp.pdf

You will notice, however, that the log-likelihood function governing the selection of the lambda power transform is dependent on the residual sum of squares of an underlying model (no LaTeX on SO -- see the reference), so no transformation can be applied without a model.

A typical application is as follows:

library(MASS)

# generate some data
set.seed(1)
n <- 100
x <- runif(n, 1, 5)
y <- x^3 + rnorm(n)

# run a linear model
m <- lm(y ~ x)

# run the box-cox transformation
bc <- boxcox(y ~ x)

(lambda <- bc$x[which.max(bc$y)])
[1] 0.4242424

powerTransform <- function(y, lambda1, lambda2 = NULL, method = "boxcox") {

  boxcoxTrans <- function(x, lam1, lam2 = NULL) {

    # if we set lambda2 to zero, it becomes the one parameter transformation
    lam2 <- ifelse(is.null(lam2), 0, lam2)

    if (lam1 == 0L) {
      log(y + lam2)
    } else {
      (((y + lam2)^lam1) - 1) / lam1
    }
  }

  switch(method
         , boxcox = boxcoxTrans(y, lambda1, lambda2)
         , tukey = y^lambda1
  )
}


# re-run with transformation
mnew <- lm(powerTransform(y, lambda) ~ x)

# QQ-plot
op <- par(pty = "s", mfrow = c(1, 2))
qqnorm(m$residuals); qqline(m$residuals)
qqnorm(mnew$residuals); qqline(mnew$residuals)
par(op)

As you can see this is no magic bullet -- only some data can be effectively transformed (usually a lambda less than -2 or greater than 2 is a sign you should not be using the method). As with any statistical method, use with caution before implementing.

To use the two parameter Box-Cox transformation, use the geoR package to find the lambdas:

library("geoR")
bc2 <- boxcoxfit(x, y, lambda2 = TRUE)

lambda1 <- bc2$lambda[1]
lambda2 <- bc2$lambda[2]

EDITS: Conflation of Tukey and Box-Cox implementation as pointed out by @Yui-Shiuan fixed.

According to the Box-cox transformation formula in the paper Box,George E. P.; Cox,D.R.(1964). "An analysis of transformations", I think mlegge's post might need to be slightly edited.The transformed y should be (y^(lambda)-1)/lambda instead of y^(lambda). (Actually, y^(lambda) is called Tukey transformation, which is another distinct transformation formula.)
So, the code should be:

(trans <- bc$x[which.max(bc$y)])
[1] 0.4242424
# re-run with transformation
mnew <- lm(((y^trans-1)/trans) ~ x) # Instead of mnew <- lm(y^trans ~ x)

More information

Correct implementation of Box-Cox transformation formula by boxcox() in R:
https://www.r-bloggers.com/on-box-cox-transform-in-regression-models/
A great comparison between Box-Cox transformation and Tukey transformation. http://onlinestatbook.com/2/transformations/box-cox.html
One could also find the Box-Cox transformation formula on Wikipedia: en.wikipedia.org/wiki/Power_transform#Box.E2.80.93Cox_transformation

Please correct me if I misunderstood it.

来源：https://stackoverflow.com/questions/33999512/how-to-use-the-box-cox-power-transformation-in-r

标签

transformation