How to allocate and free aligned memory in C

爷,独闯天下 提交于 2019-12-02 15:37:54
Jerome

Here is a solution, which encapsulates the call to malloc, allocates a bigger buffer for alignment purpose, and stores the original allocated address just before the aligned buffer for a later call to free.

// cache line
#define ALIGN 64

void *aligned_malloc(int size) {
    void *mem = malloc(size+ALIGN+sizeof(void*));
    void **ptr = (void**)((uintptr_t)(mem+ALIGN+sizeof(void*)) & ~(ALIGN-1));
    ptr[-1] = mem;
    return ptr;
}

void aligned_free(void *ptr) {
    free(((void**)ptr)[-1]);
}

Use posix_memalign/free.

int posix_memalign(void **memptr, size_t alignment, size_t size); 

void* ptr;
int rc = posix_memalign(&ptr, alignment, size);
...
free(ptr)

posix_memalign is a standard replacement for memalign which, as you mention is obsolete.

mrkj

What compiler are you using? If you're on MSVC, you can try _aligned_malloc() and _aligned_free().

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