I am using a SslServerSocket and client certificates and want to extract the CN from the SubjectDN from the client's X509Certificate.
At the moment I call cert.getSubjectX500Principal().getName() but this of course gives me the total formatted DN of the client. For some reason I am just interested in the CN=theclient part of the DN. Is there a way to extract this part of the DN without parsing the String myself?
Here's some code for the new non-deprecated BouncyCastle API. You'll need both bcmail and bcprov distributions.
X509Certificate cert = ...;
X500Name x500name = new JcaX509CertificateHolder(cert).getSubject();
RDN cn = x500name.getRDNs(BCStyle.CN)[0];
return IETFUtils.valueToString(cn.getFirst().getValue());
here is another way. the idea is that the DN you obtain is in rfc2253 format, which is the same as used for LDAP DN. So why not reuse the LDAP API?
import javax.naming.ldap.LdapName;
import javax.naming.ldap.Rdn;
String dn = x509cert.getSubjectX500Principal().getName();
LdapName ldapDN = new LdapName(dn);
for(Rdn rdn: ldapDN.getRdns()) {
System.out.println(rdn.getType() + " -> " + rdn.getValue());
}
If adding dependencies isn't a problem you can do this with Bouncy Castle's API for working with X.509 certificates:
import org.bouncycastle.asn1.x509.X509Name;
import org.bouncycastle.jce.PrincipalUtil;
import org.bouncycastle.jce.X509Principal;
...
final X509Principal principal = PrincipalUtil.getSubjectX509Principal(cert);
final Vector<?> values = principal.getValues(X509Name.CN);
final String cn = (String) values.get(0);
Update
At the time of this posting, this was the way to do this. As gtrak mentions in the comments however, this approach is now deprecated. See gtrak's updated code that uses the new Bouncy Castle API.
As an alternative to gtrak's code that does not need ''bcmail'':
X509Certificate cert = ...;
X500Principal principal = cert.getSubjectX500Principal();
X500Name x500name = new X500Name( principal.getName() );
RDN cn = x500name.getRDNs(BCStyle.CN)[0]);
return IETFUtils.valueToString(cn.getFirst().getValue());
@Jakub: I have used your solution until my SW had to be run on Android. And Android does not implement javax.naming.ldap :-(
One line with http://www.cryptacular.org
CertUtil.subjectCN(certificate);
Maven dependency:
<dependency>
<groupId>org.cryptacular</groupId>
<artifactId>cryptacular</artifactId>
<version>1.1.0</version>
</dependency>
All the answers posted so far have some issue: Most use the internal X500Name or external Bounty Castle dependency. The following builds on @Jakub's answer and uses only public JDK API, but also extracts the CN as asked for by the OP. It also uses Java 8, which standing in mid-2017, you really should.
Stream.of(certificate)
.map(cert -> cert.getSubjectX500Principal().getName())
.flatMap(name -> {
try {
return new LdapName(name).getRdns().stream()
.filter(rdn -> rdn.getType().equalsIgnoreCase("cn"))
.map(rdn -> rdn.getValue().toString());
} catch (InvalidNameException e) {
log.warn("Failed to get certificate CN.", e);
return Stream.empty();
}
})
.collect(joining(", "))
I have BouncyCastle 1.49, and the class it has now is org.bouncycastle.asn1.x509.Certificate. I looked into the code of IETFUtils.valueToString() - it is doing some fancy escaping with backslashes. For a domain name it would not do anything bad, but I feel we can do better. In the cases I've look at cn.getFirst().getValue() returns different kinds of strings that all implement ASN1String interface, which is there to provide a getString() method. So, what seems to work for me is
Certificate c = ...;
RDN cn = c.getSubject().getRDNs(BCStyle.CN)[0];
return ((ASN1String)cn.getFirst().getValue()).getString();
Here's how to do it using a regex over cert.getSubjectX500Principal().getName(), in case you don't want to take a dependency on BouncyCastle.
This regex will parse a distinguished name, giving name and val a capture groups for each match.
When DN strings contain commas, they are meant to be quoted - this regex correctly handles both quoted and unquotes strings, and also handles escaped quotes in quoted strings:
(?:^|,\s?)(?:(?<name>[A-Z]+)=(?<val>"(?:[^"]|"")+"|[^,]+))+
Here is is nicely formatted:
(?:^|,\s?)
(?:
(?<name>[A-Z]+)=
(?<val>"(?:[^"]|"")+"|[^,]+)
)+
Here's a link so you can see it in action: https://regex101.com/r/zfZX3f/2
If you want a regex to get only the CN, then this adapted version will do it:
(?:^|,\s?)(?:CN=(?<val>"(?:[^"]|"")+"|[^,]+))
Indeed, thanks to gtrak it appears that to get the client certificate and extract the CN, this most likely works.
X509Certificate[] certs = (X509Certificate[]) httpServletRequest
.getAttribute("javax.servlet.request.X509Certificate");
X509Certificate cert = certs[0];
X509CertificateHolder x509CertificateHolder = new X509CertificateHolder(cert.getEncoded());
X500Name x500Name = x509CertificateHolder.getSubject();
RDN[] rdns = x500Name.getRDNs(BCStyle.CN);
RDN rdn = rdns[0];
String name = IETFUtils.valueToString(rdn.getFirst().getValue());
return name;
Could use cryptacular which is a Java cryptographic library build on top of bouncycastle for easy use.
RDNSequence dn = new NameReader(cert).readSubject();
return dn.getValue(StandardAttributeType.CommonName);
UPDATE: This class is in "sun" package and you should use it with caution. Thanks Emil for the comment :)
Just wanted to share, to get the CN, I do:
X500Name.asX500Name(cert.getSubjectX500Principal()).getCommonName();
Regarding Emil Lundberg's comment see: Why Developers Should Not Write Programs That Call 'sun' Packages
Fetching CN from certificate is not that simple. The below code will definitely help you.
String certificateURL = "C://XYZ.cer"; //just pass location
CertificateFactory cf = CertificateFactory.getInstance("X.509");
X509Certificate testCertificate = (X509Certificate)cf.generateCertificate(new FileInputStream(certificateURL));
String certificateName = X500Name.asX500Name((new X509CertImpl(testCertificate.getEncoded()).getSubjectX500Principal())).getCommonName();
Regex expressions, are rather expensive to use. For such a simple task it will probably be an over kill. Instead you could use a simple String split:
String dn = ((X509Certificate) certificate).getIssuerDN().getName();
String CN = getValByAttributeTypeFromIssuerDN(dn,"CN=");
private String getValByAttributeTypeFromIssuerDN(String dn, String attributeType)
{
String[] dnSplits = dn.split(",");
for (String dnSplit : dnSplits)
{
if (dnSplit.contains(attributeType))
{
String[] cnSplits = dnSplit.trim().split("=");
if(cnSplits[1]!= null)
{
return cnSplits[1].trim();
}
}
}
return "";
}
X500Name is internal implemention of JDK, however you can use reflection.
public String getCN(String formatedDN) throws Exception{
Class<?> x500NameClzz = Class.forName("sun.security.x509.X500Name");
Constructor<?> constructor = x500NameClzz.getConstructor(String.class);
Object x500NameInst = constructor.newInstance(formatedDN);
Method method = x500NameClzz.getMethod("getCommonName", null);
return (String)method.invoke(x500NameInst, null);
}
You could try using getName(X500Principal.RFC2253, oidMap) or getName(X500Principal.CANONICAL, oidMap) to see which one formats the DN string best. Maybe one of the oidMap map values will be the string you want.
BC made the extraction much easier:
X500Principal principal = x509Certificate.getSubjectX500Principal();
X500Name x500name = new X500Name(principal.getName());
String cn = x500name.getCommonName();
For multi-valued attributes - using LDAP API ...
X509Certificate testCertificate = ....
X500Principal principal = testCertificate.getSubjectX500Principal(); // return subject DN
String dn = null;
if (principal != null)
{
String value = principal.getName(); // return String representation of DN in RFC 2253
if (value != null && value.length() > 0)
{
dn = value;
}
}
if (dn != null)
{
LdapName ldapDN = new LdapName(dn);
for (Rdn rdn : ldapDN.getRdns())
{
Attributes attributes = rdn != null
? rdn.toAttributes()
: null;
Attribute attribute = attributes != null
? attributes.get("CN")
: null;
if (attribute != null)
{
NamingEnumeration<?> values = attribute.getAll();
while (values != null && values.hasMoreElements())
{
Object o = values.next();
if (o != null && o instanceof String)
{
String cnValue = (String) o;
}
}
}
}
}
来源：https://stackoverflow.com/questions/2914521/how-to-extract-cn-from-x509certificate-in-java