I have some code that I want to ask the user for a number between 1-100 and if they put a number between these it will print (Size: (input)) and break the loop, if however, they put in a number outside 1-100 it will print (Size: (input)), and proceed to re-ask them for a number, I have run into some problems though.
c=100
while c<100:
c=input("Size: ")
if c == 1 or 2 or 3:
print ("Size: "+c)
break
else:
print ("Size: "+c)
print ("Invalid input. Try again.")
This should do it.
c=input("Size: ")
while int(c)>100 or int(c)<1:
#Will repeat until the number is between 1 and 100, inclusively.
#It will skip the loop if the value is between 1 and 100.
print ("Size: "+c)
print ("Invalid input. Try again.")
c=input("Size: ")
#once the loop is completed, the code following the loop will run
print ("Size: "+c)
You never even enter your loop.
c=100
while c<100:
c
is initiated at 100 and while
checks if it is less than 100.
来源:https://stackoverflow.com/questions/16073721/while-loop-user-input-in-range