PostgreSQL: How to pass table/view name as a parameter to function in PostgreSQL?

笑着哭i 提交于 2019-12-02 10:05:40

This is dynamic SQL, so you need EXECUTE.

RETURN QUERY EXECUTE format('SELECT * FROM %I', "name");

Separately, that's a weird thing to want to do.

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!