问题
I want to change the a/b inside a block to a/c (or possibly even a)
The normal way I'd do this is with change:
test: [a/b]
change test/1 'c
but it only changes the first part, i.e. a to c:
>> test
== [c/b]
Can't access the path with test/2 either:
>> reduce [test/1 test/2]
== [a/b none]
回答1:
There are 2 things to note here:
First, path! is a series, so in this case, a nested series. Have to actually access the second element inside the first element:
>> test: [a/b] test/1/2
== b
Secondly, use the property of series that make them behave like pointers and access the next element, instead of accessing it directly:
>> next test/1
== b
So the code becomes:
>> change next test/1 'c test
== [a/c]
来源：https://stackoverflow.com/questions/42696779/change-path-or-refinement