sqrt() function not working with variable arguments [duplicate]

坚强是说给别人听的谎言 提交于 2019-11-26 14:37:08

问题


This question already has an answer here:

  • Why am I getting “undefined reference to sqrt” error even though I include math.h header? [duplicate] 5 answers

I don't know if I'm missing something obvious, but it appears that I'm unable to compute square roots of a variable in C; the sqrt() function only seems to work on constants. This is my code:

#include <math.h>
#include <stdio.h>

int main()
{
    double a = 2.0;
    double b = sqrt(a);
    printf("%f", b);
    return 0;
}

When I run this program, I get the following error:

gcc -Wall -o "test2" "test2.c" (in directory: /home/eddy/Code/euler)
/tmp/ccVfxkNh.o: In function `main':
test2.c:(.text+0x30): undefined reference to `sqrt'
collect2: ld returned 1 exit status
Compilation failed.

However, if I replace the argument in sqrt() with a constant such as 2.0 for example, (b = sqrt(2.0)), then it works fine. Is sqrt() not supposed to work with variables or something?

Thanks for the help


回答1:


You need to link with the math library (use a '-lm' on the command line). In the constant case, the compiler is probably being smart and precomputing sqrt(2.0) (so the code that is compiled is essentially 'b = 1.414...;')




回答2:


You probably need to add -lm when you compile. When you take the square root of a constant, the compiler is optimizing the code by taking the square root while it compiles, so it doesn't use sqrt at all.




回答3:


Use the command gcc -Wall -o "test2" "test2.c" -lm which will likely fix this.

This includes the math library in addition to the standard C runtime library. On most systems, the math library is historically a separate entity that needs to be explicitly requested.




回答4:


In case of gcc you need to link the library.

gcc filename.c -lm .

However in case of g++ no need to link the library so this will work fine :

g++ filename.c -o filename Once compilation is successful.

To run simply enter ./filename in G++. and enter ./a.out in Gcc.




回答5:


Compile with:

gcc -Wall -o test2 test2.c -lm

You need to link against the math library.




回答6:


include math library using " " operator

#include " math.h "

compile program using -lm option for inherit math library suppose our program name is test.c the we compile as follow

gcc test.c -lm



回答7:


gcc does not link the standard libraries by default. So you just need to do this if compiling via gcc:

gcc filename.c -lm .

However in case of g++ no need to link the library so this will work fine :

g++ filename.c -o filename




回答8:


This works fine for me. I think there is some problem with ur math library. Try linking it again and see. Other wise code is completely perfect.



来源:https://stackoverflow.com/questions/3533594/sqrt-function-not-working-with-variable-arguments

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