Constexpr variable and division

我们两清 提交于 2019-12-02 03:59:49

问题


I'm trying to evaluate this simple expression at compile time using C++11 new constexpr feature:

template <int a, int b>
class Test
{
   static constexpr double c = a / b;
};

But here's what Clang keeps telling me:

Constexpr variable 'c' must be initialized by a constant expression

The weird thing is that the following compiles well:

template <int a, int b>
class Test
{
   static constexpr double c = a / 2.f;
};

Do you guys have any idea on why a/b is not a constant expression, and how could I evaluate this at compile time?

Using Clang compiler with -std=c++1y and -stdlib=libc++

Update

The following example causes the error with the original code:

Test<10,0> test1 ;

while:

Test<10,1> test1 ;

does not.


回答1:


The reason why:

Test<10,0> test1 ;

fails is because you have undefined behavior due to division by zero. This is covered in the draft C++ standard section 5.6 [expr.mul] which says:

If the second operand of / or % is zero the behavior is undefined

and constant expressions specifically exclude undefined behavior. I am not sure what version of clang you are using but the versions I have available online do provide a divide by zero warning (see it live):

note: division by zero
static constexpr double c = a / b;
                              ^



回答2:


Solved. One of the template instance had b=0. Somehow, Clang didn't warn me I was dividing by zero. And +Inf is not a constant expression.



来源:https://stackoverflow.com/questions/29222319/constexpr-variable-and-division

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