how to interrupt a scanner.nextline() call

问题

There are many threads on SO about interrupting reading the system.in but what I am looking for here is some kind of advice as to how to best code what I am trying to achieve.

I have a getlogin() method that needs to do the following: ask a user to input the desired login environnement details, if after 6 seconds user have not input a valid value ("live" or "test") then set userlogin variable to "test" and return it to the caller.

I have taken the following approach for the getlogin() implementation:

launch two threads which do the following:
- thread1 creates a scanner object then calls scanner.nextline() and depending on user input set a variable userlogin. Interrupts thread2 before exiting thread1.
- thread2 waits 6 seconds and if after that userlogin is still not set, then set a default value for userlogin. Interrupts thread1 before exiting thread2.
join thread2 to stop main Thread from returning userlogin as null
return userlogin

The problem I have with the approach is that scanner.nextline() does not interrupt when thread2 calls thread1.interrupt, which is why I do not join thread1 in step 2 as the main Thread would hang. Is there a way to get thread1 to complete after thread2 interrupts it? Or else is this approach completely overkill and there is a much simpler way to achieve the contract?

回答1:

The simplest solution is to expose the underlying stream in the "reading" thread and close that stream from the timeout thread. This should interrupt the reading and raise an exception. Handle this exception and you should be able to proceed with your logic. The only gotcha is that you won't be able to re-use the same stream again. Unfortunately there is no easy way to deal with interruption of blocking system calls.

EDIT:

Following a completely different line of reasoning; given that we can't close the input stream just to interrupt it, the only way I can think of is to use the "programmatic user input" facilities offered by the Robot class. Here is an example which works out for me:

import java.awt.Robot;
import java.awt.event.KeyEvent;
import java.util.Scanner;
import java.util.concurrent.TimeUnit;

public class ConsoleTest {

    /**
     * @param args
     */
    public static void main(String[] args) {
        new TimeoutThread().start();
        new ReaderThread().start();
    }

}

class ReaderThread extends Thread {

    @Override
    public void run() {
        System.out.print("Please enter your name: ");
        try(Scanner in = new Scanner(System.in)) {
            String name = in.nextLine();
            if(name.trim().isEmpty()) {
                name = "TEST"; // default user name
            }
            System.out.println("Name entered = " + name);
        }
    }

}

class TimeoutThread extends Thread {

    @Override
    public void run() {
        try {
            Thread.sleep(TimeUnit.SECONDS.toMillis(5));
            Robot robot = new Robot();
            robot.keyPress(KeyEvent.VK_ENTER);
            robot.keyRelease(KeyEvent.VK_ENTER);
        } catch(Exception e) {
            e.printStackTrace();
        }
    }

}

The above code uses the logic that once that timeout has expired, we simulate a newline which will cause the "name" variable to be blank. Then we have a check which performs the necessary logic and sets the appropriate user name.

The gotcha about the above approach is that it:

Uses Robot class of AWT so might not play well with headless terminals (?)
Assumes that the focus window is the console window. If the focus is somewhere else, the ENTER key-press will be registered for that window as opposed to your application window.

Hope this helps you out. I'm really out of ideas now. :)

回答2:

A FutureTask together with a lambda expression can also be used:

FutureTask<String> readNextLine = new FutureTask<String>(() -> {
  return scanner.nextLine();
});

ExecutorService executor = Executors.newFixedThreadPool(2);
executor.execute(readNextLine);

try {
  String token = readNextLine.get(5000, TimeUnit.MILLISECONDS);
  ...
} catch (TimeoutException e) {
  // handle time out
}

回答3:

Why not just poll with System.in.available() if there are bytes to read? It is non-blocking: one can do the call to Scanner.nextLine(), which is blocking, when sure it works and does not block.

回答4:

Another version of geri's answer would be:

ExecutorService executor = Executors.newFixedThreadPool(1);

Future<String> future = executor.submit(() -> {
    try (Scanner in = new Scanner(System.in)) {
        return in.nextLine();
    }
});

try {
    return future.get(5, TimeUnit.SECONDS);
} catch (InterruptedException | ExecutionException | TimeoutException e1) {
    return ...;
}

来源：https://stackoverflow.com/questions/12803151/how-to-interrupt-a-scanner-nextline-call

标签

java

java.util.scanner

interrupt