问题
This is a little difficult to explain, but i'll try my best.
This is similar to the code i'm currently running.
function func1()
{
func2()
}
function func2()
{
exit();
}
I need to be able to stop the execution of func1 from within func2, but I need a better way to do it than exit(). Since the caller of func1 might have other operations to do, I don't want to stop them as well, I just want to stop the rest of func1 from executing.
I'm aware that I could put a simple if statement in func1 to detect the return value of func2 and then return if it's a certain value, but that's a bit messy too.
So my question is, how can I stop the execution of the remainder of the caller function, from within a function?
回答1:
Return a value and check for it.
function func1()
{
$result = func2();
if ($result === 0) return;
// Your func1 code here
}
function func2()
{
if ( ... ) return 1;
else return 0;
}
回答2:
Checking a return value isn't messy. It's standard practice. You basically have two options:
- Check return values.
- Throw an exception in func2. If it's uncaught in func1 it'll bubble up higher and stop execution in both functions.
回答3:
There is absolutely no way this will work.
Remember: func2() could be called from ANYWHERE, not only func1(). How would you know that it is func1 you are stopping.
Whatever it is that made you think interrupting the calling function would solve the problem - think again, and tell us about the bigger picture for proper advice.
来源：https://stackoverflow.com/questions/19368937/php-stopping-the-execution-of-the-calling-function