Convert a string date into datetime in Oracle

问题

How can I convert this string date to datetime in oracle.

2011-07-28T23:54:14Z

Using this code throws an error:

TO_DATE('2011-07-28T23:54:14Z',  'YYYY-MM-DD HH24:MI:SS')

How can this be done?

Error report:
SQL Error: ORA-01861: literal does not match format string
01861. 00000 -  "literal does not match format string"
*Cause:    Literals in the input must be the same length as literals in
           the format string (with the exception of leading whitespace).  If the
           "FX" modifier has been toggled on, the literal must match exactly,
           with no extra whitespace.
*Action:   Correct the format string to match the literal.

Update:-

TO_DATE('2011-07-28T23:54:14Z', 'YYYY-MM-DD"T"HH24:MI:SS"Z"')

I only see the date not time in the column

28-JUL-11

回答1:

Try this: TO_DATE('2011-07-28T23:54:14Z', 'YYYY-MM-DD"T"HH24:MI:SS"Z"')

回答2:

Hey I had the same problem. I tried to convert '2017-02-20 12:15:32' varchar to a date with TO_DATE('2017-02-20 12:15:32','YYYY-MM-DD HH24:MI:SS') and all I received was 2017-02-20 the time disappeared

My solution was to use TO_TIMESTAMP('2017-02-20 12:15:32','YYYY-MM-DD HH24:MI:SS') now the time doesn't disappear.

回答3:

You can use a cast to char to see the date results

 select to_char(to_date('17-MAR-17 06.04.54','dd-MON-yy hh24:mi:ss'), 'mm/dd/yyyy hh24:mi:ss') from dual;

来源：https://stackoverflow.com/questions/7920637/convert-a-string-date-into-datetime-in-oracle