Submitting form data without reloading page

问题

I am trying to submit the form without reloading the page itself using the jQuery, but the data is not showing up and the form is reloading, which is not needed.

jQuery code:

function submitFormData() {
var firstval = $("#first").val();
var second = $("#second").val();
//var operator = $("#myselect option:selected" ).text();
$.post("index.php",{first:first,second:second},
function(data){
    $('#results').html(data);
    $('#formcal')[0].reset();
});
}

THIS IS THE HTML CODE ON THE SAME PAGE(INDEX.PHP):

<form action="" id="formcal" method="post">

<input type="number" id="first" name="first" placeholder="number"/>
<select name="operator" id="operator">
<option value="add">+</option>
<option value = "subtract">-</option>
<option value = "multiply">*</option>
<option value = "division">/</option>


</select>
<input type="number" id="second" name="second" placeholder="number 2"/>
<input type="button" id="submitFormData" onclick="SubmitFormData();" value="Calculate"/>
</form>

<br>
<?php //if(!empty($_POST['first']) && !empty($_POST['second'])){
        $number = $_POST['first'];
        $number2 = $_POST['second'];

        echo "Answer:  ";
        if($_POST['operator'] == 'add'){
            $complete = $number + $number2;
            echo " $number + $number2 = $complete";
        }
        if($_POST['operator'] == 'subtract'){
            $complete = $number - $number2;
            echo "$number - $number2 = $complete";
        }
        if($_POST['operator'] == 'multiply'){
            $complete = $number * $number2;
            echo "$number X  $number2 = $complete";
        }
        if($_POST['operator'] == 'division'){
            $complete = $number / $number2;
            echo "$number / $number2 = $complete";
        }
    //} 
    ?>
</div>

<div id="results">
</div>

回答1:

Prevent the default action of the form submit.

function submitFormData(event) {
   // prevent the default action
   event.preventDefault();

   // Other pieces of code

回答2:

You can use the onsubmit event on the form itself.

<form action="" id="formcal" method="post" onsubmit="return SubmitFormData();">

<input type="number" id="first" name="first" placeholder="number"/>
<select name="operator" id="operator">
<option value="add">+</option>
<option value = "subtract">-</option>
<option value = "multiply">*</option>
<option value = "division">/</option>


</select>
<input type="number" id="second" name="second" placeholder="number 2"/>
<input type="submit" id="submitFormData"  value="Calculate"/>
</form>
<script>
  function SubmitFormData(){
alert("triggered submit function");
return false;

}
  </script>
<br>
<?php //if(!empty($_POST['first']) && !empty($_POST['second'])){
        $number = $_POST['first'];
        $number2 = $_POST['second'];

        echo "Answer:  ";
        if($_POST['operator'] == 'add'){
            $complete = $number + $number2;
            echo " $number + $number2 = $complete";
        }
        if($_POST['operator'] == 'subtract'){
            $complete = $number - $number2;
            echo "$number - $number2 = $complete";
        }
        if($_POST['operator'] == 'multiply'){
            $complete = $number * $number2;
            echo "$number X  $number2 = $complete";
        }
        if($_POST['operator'] == 'division'){
            $complete = $number / $number2;
            echo "$number / $number2 = $complete";
        }
    //}

来源：https://stackoverflow.com/questions/34404512/submitting-form-data-without-reloading-page

标签

javascript

jquery

html

submit

reload