How to give executable permission to all Python scripts in Linux?

Suppose I have a python script called a.py like this:

#!/usr/bin/env python3
# -*- coding: utf-8 -*-
# Author    : Bhishan Poudel
# Date      : Jul 13, 2016


# Imports


# Script
print("hello")

I can run this scripts in two ways:
Using python interpreter:

python3 a.py

Changing permission

chmod a+x a.py; ./a.py

QUESTION
How can I run any new or old python scripts without using chmod a+x script_name all the times.

I have root access and user access both to my computer.

Basically i want executable permission to all the .py files, how can we do so?

I tried different shebangs such as:

#!/usr/bin/python3
#!/usr/bin/env python3
#!/usr/local/bin/python3
#!/usr/local/bin/env python3

The python interpreter is also in the $PATH. The output of echo $PATH is following:

/Library/Frameworks/Python.framework/Versions/2.7/bin:/Library/Frameworks/Python.framework/Versions/3.5/bin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin:/opt/X11/bin:/usr/texbin:/Library/Frameworks/Python.framework/Versions/2.7/bin:/Library/Frameworks/Python.framework/Versions/3.5/bin:/opt/local/bin:/Users/poudel/phosim:/Users/poudel/Applications:/usr/local/octave/3.8.0/bin:/Users/poudel/Applications/Geany.app/Contents/MacOS/:/opt/local/bin:/Users/poudel/phosim:/Users/poudel/Applications:/usr/local/octave/3.8.0/bin:/Applications/Geany.app/Contents/MacOS/:/opt/local/bin:/Users/poudel/phosim:/Users/poudel/Applications:/usr/local/octave/3.8.0/bin:/Applications/Geany.app/Contents/MacOS/

Also, ls /usr/bin/py* has:

/usr/bin/pydoc*            /usr/bin/python2.5@        /usr/bin/pythonw*
/usr/bin/pydoc2.5@         /usr/bin/python2.5-config@ /usr/bin/pythonw2.5@
/usr/bin/pydoc2.6@         /usr/bin/python2.6@        /usr/bin/pythonw2.6@
/usr/bin/pydoc2.7@         /usr/bin/python2.6-config@ /usr/bin/pythonw2.7@
/usr/bin/python*           /usr/bin/python2.7@
/usr/bin/python-config*    /usr/bin/python2.7-config@

sjsam

The hard way

Run below with root privilege:

find /your/path/ -type f -name "*.py" -exec chmod u+x {} \;

Note:

chmod need not be run as root if you're the owner of .py file.

The smart way

Write a script to take care of this.

#!/bin/bash
if [ -f "$1" ]
then
geany "$1" # You could also use xdg-open if you set geany to open .py files
else
cp /path/to/python/startup/template "$1" # You may omit this if you don't have a default template
chmod u+x "$1"
geany "$1"
fi

Save the script as, say, pycreator in say /usr/bin/ , then do

chown root:root /usr/bin/pycreator
chmod +x-w /usr/bin/pycreator

To create a new script using pycreator, do

pycreator calculator.py

Also [ this ] answer pointed to by @choroba in his comment provides valuable insight in this regard.

Using the idea of @sjsam, I did following:

Suppose I have a file hello.py in any location.

cd to that location
find $PWD -type f -name "*.py" -exec chmod u+x {} \;
./hello.py

# Now, i can create any number of .py files in that folder and run ./filename

# Note: if we are running as user permission, and also have sudo access,
   we can also do:
   sudo -H find $PWD -type f -name "*.py" -exec chmod u+x {} \;

We should not use sudo unless absolutely necessary.

Thanks to sjsam.

Just type this command in terminal.