I am using local windows and trying to load the XML file with the following code on python, and i am having this error, do anyone knows how to resolve it,
this is the code
df1 = sqlContext.read.format("xml").options(rowTag="IRS990EZ").load("https://irs-form-990.s3.amazonaws.com/201611339349202661_public.xml")
and this is the error
Py4JJavaError Traceback (most recent call last)
<ipython-input-7-4832eb48a4aa> in <module>()
----> 1 df1 = sqlContext.read.format("xml").options(rowTag="IRS990EZ").load("https://irs-form-990.s3.amazonaws.com/201611339349202661_public.xml")
C:\SPARK_HOME\spark-2.2.0-bin-hadoop2.7\python\pyspark\sql\readwriter.py in load(self, path, format, schema, **options)
157 self.options(**options)
158 if isinstance(path, basestring):
--> 159 return self._df(self._jreader.load(path))
160 elif path is not None:
161 if type(path) != list:
C:\SPARK_HOME\spark-2.2.0-bin-hadoop2.7\python\lib\py4j-0.10.4-src.zip\py4j\java_gateway.py in __call__(self, *args)
1131 answer = self.gateway_client.send_command(command)
1132 return_value = get_return_value(
-> 1133 answer, self.gateway_client, self.target_id, self.name)
1134
1135 for temp_arg in temp_args:
C:\SPARK_HOME\spark-2.2.0-bin-hadoop2.7\python\pyspark\sql\utils.py in deco(*a, **kw)
61 def deco(*a, **kw):
62 try:
---> 63 return f(*a, **kw)
64 except py4j.protocol.Py4JJavaError as e:
65 s = e.java_exception.toString()
C:\SPARK_HOME\spark-2.2.0-bin-hadoop2.7\python\lib\py4j-0.10.4-src.zip\py4j\protocol.py in get_return_value(answer, gateway_client, target_id, name)
317 raise Py4JJavaError(
318 "An error occurred while calling {0}{1}{2}.\n".
--> 319 format(target_id, ".", name), value)
320 else:
321 raise Py4JError(
Py4JJavaError: An error occurred while calling o38.load.
: java.io.IOException: No FileSystem for scheme: https
at org.apache.hadoop.fs.FileSystem.getFileSystemClass(FileSystem.java:2660)
at org.apache.hadoop.fs.FileSystem.createFileSystem(FileSystem.java:2667)
at org.apache.hadoop.fs.FileSystem.access$200(FileSystem.java:94)
at org.apache.hadoop.fs.FileSystem$Cache.getInternal(FileSystem.java:2703)
at org.apache.hadoop.fs.FileSystem$Cache.get(FileSystem.java:2685)
at org.apache.hadoop.fs.FileSystem.get(FileSystem.java:373)
at org.apache.hadoop.fs.Path.getFileSystem(Path.java:295)
at org.apache.hadoop.mapreduce.lib.input.FileInputFormat.setInputPaths(FileInputFormat.java:500)
at org.apache.hadoop.mapreduce.lib.input.FileInputFormat.setInputPaths(FileInputFormat.java:469)
at org.apache.spark.SparkContext$$anonfun$newAPIHadoopFile$2.apply(SparkContext.scala:1160)
at org.apache.spark.SparkContext$$anonfun$newAPIHadoopFile$2.apply(SparkContext.scala:1148)
at org.apache.spark.rdd.RDDOperationScope$.withScope(RDDOperationScope.scala:151)
at org.apache.spark.rdd.RDDOperationScope$.withScope(RDDOperationScope.scala:112)
at org.apache.spark.SparkContext.withScope(SparkContext.scala:701)
at org.apache.spark.SparkContext.newAPIHadoopFile(SparkContext.scala:1148)
at com.databricks.spark.xml.util.XmlFile$.withCharset(XmlFile.scala:46)
at com.databricks.spark.xml.DefaultSource$$anonfun$createRelation$1.apply(DefaultSource.scala:62)
at com.databricks.spark.xml.DefaultSource$$anonfun$createRelation$1.apply(DefaultSource.scala:62)
at com.databricks.spark.xml.XmlRelation$$anonfun$1.apply(XmlRelation.scala:47)
at com.databricks.spark.xml.XmlRelation$$anonfun$1.apply(XmlRelation.scala:46)
at scala.Option.getOrElse(Option.scala:121)
at com.databricks.spark.xml.XmlRelation.<init>(XmlRelation.scala:45)
at com.databricks.spark.xml.DefaultSource.createRelation(DefaultSource.scala:65)
at com.databricks.spark.xml.DefaultSource.createRelation(DefaultSource.scala:43)
at org.apache.spark.sql.execution.datasources.DataSource.resolveRelation(DataSource.scala:306)
at org.apache.spark.sql.DataFrameReader.load(DataFrameReader.scala:178)
at org.apache.spark.sql.DataFrameReader.load(DataFrameReader.scala:156)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
at java.lang.reflect.Method.invoke(Unknown Source)
at py4j.reflection.MethodInvoker.invoke(MethodInvoker.java:244)
at py4j.reflection.ReflectionEngine.invoke(ReflectionEngine.java:357)
at py4j.Gateway.invoke(Gateway.java:280)
at py4j.commands.AbstractCommand.invokeMethod(AbstractCommand.java:132)
at py4j.commands.CallCommand.execute(CallCommand.java:79)
at py4j.GatewayConnection.run(GatewayConnection.java:214)
at java.lang.Thread.run(Unknown Source)
Somehow pyspark is unable to load the http or https, one of my colleague found the answer for this so here is the solution,
before creating the spark context and sql context we need to load this two line of code
import os
os.environ['PYSPARK_SUBMIT_ARGS'] = '--packages com.databricks:spark-xml_2.11:0.4.1 pyspark-shell'
after creating the sparkcontext and sqlcontext from sc = pyspark.SparkContext.getOrCreate and sqlContext = SQLContext(sc)
add the http or https url into the sc by using sc.addFile(url)
Data_XMLFile = sqlContext.read.format("xml").options(rowTag="anytaghere").load(pyspark.SparkFiles.get("*_public.xml")).coalesce(10).cache()
this solution worked for me
The error message says it all: you cannot use dataframe reader & load to access files on the web (http or htpps). I suggest you first download the file locally.
See the pyspark.sql.DataFrameReader docs for more on the available sources (in general, local file system, HDFS, and databases via JDBC).
Irrelevantly to the error, notice that you seem to use the format part of the command incorrectly: assuming that you use the XML Data Source for Apache Spark package, the correct usage should be format('com.databricks.spark.xml') (see the example).
I've commit a similar but slightly different error: forgot the "s3://" prefix to file path. After adding this prefix to form "s3://path/to/object" the following code works:
my_data = spark.read.format("com.databricks.spark.csv")\
.option("header", "true")\
.option("inferSchema", "true")\
.option("delimiter", ",")\
.load("s3://path/to/object")
来源：https://stackoverflow.com/questions/47352813/pyspark-java-io-ioexception-no-filesystem-for-scheme-https