zipfile

I am trying to download a zip file from a dotnet core web api action, but I can't make it work. I tried calling the action via POSTMAN and my Aurelia Http Fetch Client. I am able to create the ZipFile like I want it and store it on the system, but can't fix it so it returns the zipfile via the api. Use-case: User selects a couple of picture collections and clicks the download button. The ids of the picture collections gets send to the api and a zipfile is created which contains a directory for every picture collection which holds the pictures. That zipfile is returned to the user so he/she can

I want to read the contents of a zip file into memory rather than extracting them to disc, find a particular file in the archive, open the file and extract a line from it. Can a StringIO instance be opened and parsed? Suggestions? Thanks in advance. zfile = ZipFile('name.zip', 'r') for name in zfile.namelist(): if fnmatch.fnmatch(name, '*_readme.xml'): name = StringIO.StringIO() print name # prints StringIO instances open(name, 'r') # IO Error: No such file or directory... I found a few similar posts, but none that seem to address this issue: Extracting a zipfile to memory? IMO just using read

Using python zipfile module I created a zip file as follows: s = StringIO() zip_file = zipfile.ZipFile(s, "w") zip_file.write('/local/my_files/my_file.txt') s.seek(0) and now, I want this zip_file to be saved in my file system at path /local/my_files/ as my_file.zip . Generally to save a noraml files I used the following flow: with open(dest_file, 'w') as out_file: for line in in_file: out_file.write(line) But, I think I can't achieve saving a zipfile with this. Can any one please help me in getting this done. zip_file = zipfile.ZipFile("/local/my_files/my_file.zip", "w") zip_file.write('

This question already has an answer here: Python code to create a password encrypted zip file? [duplicate] 5 answers I have a zipfile in (sav.zip) and I'm trying to set a Password for it: zf = zipfile.ZipFile("sav.zip") zf.setpassword("1234") but... I get a TypeError: expected Bytes, got str Where's my mistake? It is not mentioned in the documentation, but on Python 3, the password should be bytes , not str . So: zf.setpassword(b"1234") Note that the password is only used for reading , not writing! See the docstring for ZipFile.open in Python 3. The ZipFile class can read "pkzip 2.0"

I'm trying to use zipfile library on windows 8.1 and python 2.7.9. I just want to remove library.zip after zipfile.open() but os.remove() throws "WindowsError [Error 32]" and it seems zipfile doesn't release the zip file out of with block. WindowsError 32 means "The process cannot access the file because it is being used by another process." So, how can I remove this library.zip file? code: import os import zipfile as z dirs = os.listdir('build/') bSystemStr = dirs[0] print("[-] Merging library.zip...") with z.ZipFile('build/' + bSystemStr + '/library.zip', 'a') as z1: with z.ZipFile('build

I have been wracking my brains in this problem. Is there a way in django to serve multiple files from a single HttpResponse? I have a scenario where i am looping through a list of json and want to return all those as file form my admin view. class CompanyAdmin(admin.ModelAdmin): form = CompanyAdminForm actions = ['export_company_setup'] def export_company_setup(self, request, queryset): update_count = 0 error_count = 0 company_json_list = [] response_file_list = [] for pb in queryset.all(): try: # get_company_json_data takes id and returns json for the company. company_json_list.append(get