zend-framework

问题 i would like to take messages from amazon sqs in the same order in which it is inserted into sqs ( first in first out model). Is their any way to implement it?? I am using zend php for programing. 回答1: Unordered message delivery is inherent in the design of SQS. You could try to work around it by numbering the messages and storing the out-of-order messages locally until the missing messages arrive, but its probably not worth the hassle. SQS is really a bit of an odd duck, it does what it says

问题 i would like to take messages from amazon sqs in the same order in which it is inserted into sqs ( first in first out model). Is their any way to implement it?? I am using zend php for programing. 回答1: Unordered message delivery is inherent in the design of SQS. You could try to work around it by numbering the messages and storing the out-of-order messages locally until the missing messages arrive, but its probably not worth the hassle. SQS is really a bit of an odd duck, it does what it says

问题 I'm using Doctrine with Zend Framework. I have to create both the DB schema and the Doctrine entities with annotations. Since the annotations already contain the information, it should be possible to create/update the schema based on them. I don't want to reinvent the wheel, so I was wondering whether that kind of logic already existed? 回答1: You can use the doctrine CLI, for a lot of doctrine related tasks. I'm not sure how doctrine is integrated into Zend, but look for the doctrine.php, and

问题 My zend application structure: application ->configs ->layouts ->scripts ->admin.phtml ->site.phtml ->modules ->admin(controllers, models, views) ->Bootstrap.php ->default(controller,models,views) ->Bootstrap.php I have set the default layout in my application.ini as: resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts" resources.layout.layout = "site" I have two modules: admin and default. How to set the layout file (admin.phtml)for admin module? I want to change the layout from

问题 Zend framework i have directory tree as following with robots.txt file, but when i browse www.site.com/robots.txt , it says page not found error. How do i tell ZF that robots.txt is allowed? A. Directory tree: wwwsite/application wwwsite/library wwwsite/ZendFramework-1.10.7.tar.gz wwwsite/public . |--- captcha | |--- css |--- js |--- img |--- files | .htaccess index.php robots.txt B. .htaccess RewriteEngine On RewriteCond %{REQUEST_FILENAME} -s [OR] RewriteCond %{REQUEST_FILENAME} -l [OR]

问题 I'm having trouble getting the Zend_Controller_Router_Route_Hostname to work properly. I'm using Zend Framework 1.9.4 In my config I have: resources.router.routes.www.type = "Zend_Controller_Router_Route_Hostname" resources.router.routes.www.route = ":module.domain" resources.router.routes.www.defaults.module = "frontend" resources.router.routes.www.chains.index.type = "Zend_Controller_Router_Route" resources.router.routes.www.chains.index.route = ":controller/:action/*" resources.router

问题 I have a form on my index, and when it valid, it redirects to a new view, and i want on that new view to get the name that was entered in the form, how can i do that? my controller: public function indexAction() { // action body $eform = new Application_Form_Eform(); if ($this->_request->isPost()) { $formData = $this->_request->getPost(); if ($eform->isValid($formData)) { $nameInput = $eform->getValue('nameInput'); $this->_helper->redirector->gotoRoute(array('controller'=> 'index','action' =>

问题 public function thisMethod { $example = $this->methodReturnsObject()->this1->that2->there3->id; return $example; } How would you test thisMethod in PHPUnit? Obviously I could write an expectation that methodReturnsObject() will return something... but what? That object has properties associated with it, but how would you even mock that value? 回答1: The answer is "You don't". Unit testing should test each class in isolation, what you are trying to do there is not a unit test. As I said in my

问题 I'm trying to detect which controller I'm using or what controller I'm on and then change my menu accordingly to the page I'm on. ( Make a selection in the menu so the user can see were he is on the page! ) I really don't know what to write to check what it's using... <? if($this->url(array("controller" => "index", "action" => "index"), null, true)) { echo("LOL"); } ?> I tried that but that stuff didn't work at all, I know it's the wrong thing to use, so please help me =D 回答1: You can get

问题 I am struggeling getting content/code assist to work for PHP libraries (other than Zend) in my Zend Framework project folder: library Doctrine Zend (<-works with code assist...) ZendX Content assist remains blank when using this libraries... Any suggestions? Thanks, Udo 回答1: Content Assist is available for any compatible resources in the include path. Right click your project folder. Then Include Path . Then Configure Include Path . A window will appear. Configure any needed resources.