xor

XOR neural network does not learn

由 拜拜、爱过 提交于 2019-12-08 07:55:09
问题 I am trying to solve the very simple non-linear problem. It is XOR gate. I my school knowledge. XOR can be solve by using 2 input nodes, 2 hidden layer nodes. And 1 output. It is binary classification problem. I generate the 1000 of random integer number it is 0 or 1 and then do backpropagation. But for some unknown reason my network has not learned anything. The training accuracy is constant at 50 . # coding: utf-8 import matplotlib import torch import torch.nn as nn from torch.autograd

How to XOR md5 hash values and cast them to HEX in postgresql

由 扶醉桌前 提交于 2019-12-08 01:46:42
问题 What I have tried so far SELECT md5(text) will return text (hex strings) . After that We need to xor them SELECT x'hex_string' # x'hex_string'; But the above results in binary values. How do I again convert them into hex string? Is there anyway to xor md5 values in postgresql and convert this into hexadecimal values again ? 回答1: Those binary values are in fact of type bit varying , which differs significantly from bytea . bit varying comes with built-in support for XOR and such, but

PHP Bitwise XOR vs. JavaScript Bitwise XOR

由 爷，独闯天下 提交于 2019-12-07 18:38:22
问题 I'm trying to find a way to make PHP Bitwise XOR results match the results of JavaScript Bitwise XOR . I came across different questions of this issue, and all without answers. Here are a few of them: Javascript & PHP Xor equivalent php bitwise XOR and js bitwise XOR producing different results JS bitwise XOR operator acts differently from PHP’s counterpart. How to get the same result as PHP returns? I know that PHP is using 64 bit compared to 32 bit JavaScript, but my question is, is there

Find the two non-repeating elements in an array of repeating element XOR operator?

由 筅森魡賤 提交于 2019-12-07 05:18:29
问题 Suppose I have an array with 2n+2 elements. n elements in array are occurring twice and remaining two elements are unique. You have to solve this in O(n) time and O(1) space. One of the solution is using XOR. But I am not able to understand that. Can anyone help me regarding that or can give me better solution ? Link of the Problem and solution is this 回答1: First - note that a xor a == 0 , for each a . Let's say you have two unique numbers - x,y . If you do xor on each element, you end up

Swift Simple XOR Encryption

由 岁酱吖の 提交于 2019-12-07 04:44:28
问题 I am trying to do a simple xor encryption routine in Swift. I know this is not a particularly secure or great method but I just need it to be simple. I know how the code is implemented in Javascript I'm just having trouble translating it to Swift. Javascript: function xor_str() { var to_enc = "string to encrypt"; var xor_key=28 var the_res="";//the result will be here for(i=0;i<to_enc.length;++i) { the_res+=String.fromCharCode(xor_key^to_enc.charCodeAt(i)); } document.forms['the_form']

Xor encryption in PHP

由 一个人想着一个人 提交于 2019-12-07 00:15:25
问题 I'm new to Xor encryption, and I'm having some trouble with the following code: function xor_this($string) { // Let's define our key here $key = ('magic_key'); // Our plaintext/ciphertext $text =$string; // Our output text $outText = ''; // Iterate through each character for($i=0;$i<strlen($text);) { for($j=0;$j<strlen($key);$j++,$i++) { $outText .= $text{$i} ^ $key{$j}; //echo 'i='.$i.', '.'j='.$j.', '.$outText{$i}.'<br />'; //for debugging } } return $outText; } When I run this it works for

PHP Bitwise XOR vs. JavaScript Bitwise XOR

由 这一生的挚爱 提交于 2019-12-06 15:06:18
I'm trying to find a way to make PHP Bitwise XOR results match the results of JavaScript Bitwise XOR . I came across different questions of this issue, and all without answers. Here are a few of them: Javascript & PHP Xor equivalent php bitwise XOR and js bitwise XOR producing different results JS bitwise XOR operator acts differently from PHP’s counterpart. How to get the same result as PHP returns? I know that PHP is using 64 bit compared to 32 bit JavaScript, but my question is, is there any manual way to count similar results? How can we make PHP get similar results as JS? If the numbers

XOR neural network does not learn

由 女生的网名这么多〃 提交于 2019-12-06 14:54:15
I am trying to solve the very simple non-linear problem. It is XOR gate. I my school knowledge. XOR can be solve by using 2 input nodes, 2 hidden layer nodes. And 1 output. It is binary classification problem. I generate the 1000 of random integer number it is 0 or 1 and then do backpropagation. But for some unknown reason my network has not learned anything. The training accuracy is constant at 50 . # coding: utf-8 import matplotlib import torch import torch.nn as nn from torch.autograd import Variable matplotlib.use('TkAgg') # My buggy OSX 10.13.6 requires this import matplotlib.pyplot as

How to XOR md5 hash values and cast them to HEX in postgresql

由 回眸只為那壹抹淺笑 提交于 2019-12-06 14:15:21
What I have tried so far SELECT md5(text) will return text (hex strings) . After that We need to xor them SELECT x'hex_string' # x'hex_string'; But the above results in binary values. How do I again convert them into hex string? Is there anyway to xor md5 values in postgresql and convert this into hexadecimal values again ? Those binary values are in fact of type bit varying , which differs significantly from bytea . bit varying comes with built-in support for XOR and such, but PostgreSQL doesn't provide a cast from bit varying to bytea . You could write a function that does the cast, but it's

XOR two Binary Strings c++

由 房东的猫 提交于 2019-12-06 12:45:06
I have two strings as follows : STRING1 : 011011110011000 STRING2 : 011001000001000 EXPECTED OUTPUT : 000010110010000 However, when i try to XOR them(bit-wise) using the following code, the output is blank. Code: for(int i = 0; i<15; i++) { final_key[i] = STRING1[i] ^ STRING2[i]; cout<<" XOR = "<<final_key[i]; } Any help would be appreciated. You are trying to XOR 2 char at a time. Try instead: final_key[i] = ((STRING1[i]-'0') ^ (STRING2[i]-'0')) + '0'; Explanation Refer to here for ASCII values. The ASCII value for '0' is 48 and the ASCII value of '1' is 49. 48 ^ 49 is 1, 48 ^ 48 and 49 ^ 49
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