x86-16

I need to prompt to user a msg that tells him to write a number , then I store this number and do some operation on it After searching in INT 21h I found this : INT 21h / AH=1 - read character from standard input, with echo, result is stored in AL. if there is no character in the keyboard buffer, the function waits until any key is pressed. example: mov ah, 1 int 21h The main problem that this only reads one character and represent it as ASCII so If I need to write the number "357" I will read it as 3 , 5 , 7 and this is not my goal . any ideas ? When you managed to get the user input , put

I am trying to assign variable to register here is the code: ORG 100h var1 DB 10 ; var2 DB 20 ; MOV BX,var1 ; error : operands do not match: 16 bit register and 8 bit address RET END But if swap the 4th line with: MOV BL, var1; it works. So my question is why can’t I move 8 bit variable into much larger 16 bit register ? I have already referred this , this and this OP but it does not answer my question. NOTE: I am using emu8086 assembler I am new to assembly language so I apologise if it's a stupid question. why can’t I move 8 bit variable into much larger 16 bit register? Becase the machine

I implemented the multiplication of two big integer in emu8086 with code as below : ; MULTIPLY N1 * N2 = RES MULTIPLY PROC MOV BH, 0H MOV CH, 0H MOV CL, L1; initial counter of first loop ( L1 -> length of N1 ) DEC CX MUL_1: MOV COUNTER, CL ; store counter of first loop MOV CL, L2 ; initial counter of second loop ( L2 -> length of N2 ) MUL_2: MOV BH, 0H MOV BL, COUNTER DEC BL MOV AL, N1[BX] ; get BX th byte of N1 MOV BL, CL DEC BL MUL N2[BX] ; multiple N1 and N2 's bytes MOV BH, 0H MOV BL, COUNTER ADD BX, CX DEC BX ADD RES[BX], AL ; AL should be add into RES[loop1_counter + loop2_counter - 1]

I've been struggling a lot with the error "jmp out of range", a lot of times I need to run a subrutine from different parts of my code as I would a function in C++. I got to a point that both ends on my code need to jump to the same place and there is just no way for both to get there. What is the solution for this? Also I noticed that PRINT 'something' Seems to occupy more "space" than using: CALL PTHIS DB 13, 10, 'something', 0 (If I put a PRINT between two jumps I get jump out of range but if I replace it with a PTHIS there is no problem) Why is this? Jim Mischel The problem with the

My problem is that I have written a code that is supposed to output a result into a set of LEDs connected to the parallel port. When I ran the code it pretty much did nothing. My instructor told me that the code ran too fast that my eyes did not see what happened. I have found that there are a couple of ways to do a time delay, I have tried to loop the NOP but I think I cannot really determine what is going on. Is there any better way? I have here a part of the code where I have to add a time delay into: org 100h mov ax, 0 mov dx, 378 out dx, ax mov ax, 1 ; 1st mov cx, 1ah start1st: mov ax, 1

Can anyone explain to me these pointers with a suitable example ... and when these pointers are used? In the old days, according to the Turbo C manual, a near pointer was merely 16 bits when your entire code and data fit in the one segment. A far pointer was composed of a segment as well as an offset but no normalisation was performed. And a huge pointer was automatically normalised. Two far pointers could conceivably point to the same location in memory but be different whereas the normalised huge pointers pointing to the same memory location would always be equal. The primary example is the