x86-16

I have a pointer to an array, DI. Is it possible to go to the value pointed to by both DI and another pointer? e.g: mov bl,1 mov bh,10 inc [di+bl] inc [di+bh] And, on a related note, is there a single line opcode to swap the values of two registers? (In my case, BX and BP?) Zooba For 16-bit programs, the only supported addressing forms are: [BX+SI] [BX+DI] [BP+SI] [BP+DI] [SI] [DI] [BP] [BX] Each of these may include either an 8- or 16-bit constant displacement. (Source: Intel Developer's Manual volume 2A , page 38) The problem with the example provided is that bl and bh are eight-bit

;The number of repetition of each character in the string .MODEL small .STACK 100h .DATA msg3 db 13,10,'Enter a string up to 200 characters:$' msg4 db ' $' msg5 db 13,10,'Hit any key to exit',13,10,'$' crlf db 13,10,'$' char db 0 repet db 0 mone1 dw 0 mone2 dw 0 dig1 db 0 dig2 db 0 dig3 db 0 arr db 256 dup(0) str db 200 strlen db 0 strtxt db 200 dup(0) .CODE mov AX,@data mov DS,AX call GetString call UpdateArr call Repetitions call EndProject GetString: lea DX,msg3 ;Show msg3 on screen mov AH,09h int 21h lea DX,str ;Accept a string mov AH,0ah int 21h lea DX,crlf ;New line for the output mov AH

Is there any way to change every flag manually? Or do you have to use a command with a result that you know will change them? Basically I'm working with the command RCL , and I don't want to get 1 at the begining, so I want to change the CF to 0, and I know that I can use commands like: mov al, 0 shl al, 1 But I want to know if there is any other way to do that, without the use of another commands result. I would also want to know whether the way you may show me, can also be used to change all of the flags, not only CF, but OF, ZF, and so on. There isn't any instruction that treat eflags as