wsgi

问题 Is there any way to wrap a WSGI application method such the server will send a response when a particular method is called, rather than when the application method returns a sequence? Basically, I'd like to have the equivalent of a finish_response(responseValue) method. 回答1: WSGI app must return an iterable, one way or another. If you want to send partial responses, turn your application into a generator (or return an iterator): import wsgiref, wsgiref.simple_server, time def app(environ,

问题 I have a couple of python 3.6 Flask apps running on my apache server using WSGI. There are 2 different apps running on the same apache server: www.example.com/lodge www.example.com/dashboard Both apps have a unique app.secret_key The /dashboard app is a flask app with its own set of routes: /dashboard/login /dashboard/orders /dashboard/staff The login route calls session.clear() and lets the user enter their login information. A logged in token then gets stored in a session variable. Both the

问题 I'm using Gunicorn to run my Flask website in production. It all works fine, but when deploying updates I always stop and start the server again. I now read about this reload flag which "restarts workers when code changes" which according to the docs is " intended for development ". If I could use this in production it would prevent the need to stop & restart gunicorn when deploying. What is the reason that I should not use auto-reload in production? 回答1: The reload flag can be used in

问题 Centos 5.5 comes with python 2.4 installed, and I needed python 2.7 for a project. I downloaded the source, ran, removed, and tried again with a couple alternative builds: ./configure && make && make install ./configure && make && make altinstall ./configure --prefix=/opt/python2.7 && make && make install I proceeded to install setuptools and virtualenv (making sure to reference the correct version of python, no symlinks or anything else weird). Built a virtualenv for the project, configured

问题 Here's a Flask app that can be run either from the command-line or via Apache/WSGI: import flask app = flask.Flask(__name__) LENGTH = 1000000 # one million @app.route('/', methods=['HEAD']) def head(): return 'x' * LENGTH # response body isn't actually sent @app.route('/', methods=['GET']) def get(): import random return ''.join(str(random.randint(0,9)) for x in range(LENGTH)) if __name__ == '__main__': app.run() # from command-line else: application = app # via Apache and WSGI I.e., this app

问题 When running Bottle as a standalone server it's very easy to do: from bottle import run, Bottle run(app=app, host=config.get('bottle_host', 'localhost'), port=config.get('bottle_port', '8080'), debug=config.get('debug', True), server=config.get('server_middleware', 'tornado')) The problem is that with wsgi I have to do this: app = Bottle() And Bottle constructor doesn't have any debug parameter. So what can I do to get the stacktrace? 回答1: import bottle bottle.debug(True) If you look at the

问题 Is there a way to pass extra arguments to WSGIScriptAlias? For example: WSGIScriptAlias / /foo/bar/wsgi.py but what I want is: WSGIScriptAlias / /foor/bar/wsgi.py baz Edit for clarification : I have a Django project with multiple configurations based on the environment in which it is running (cloud-based deployment). Currently, I'm loading configuration based on hostname (which I'm not overly happy with because it doesn't lend itself well to testing multiple configs on one machine without

问题 The following codes are working without any problem in my system's localhost... But ain't doing the job on OpenShift.. There is something wrong with my wsgi.py .. Do I have to pass my username and password using environment variables OR I've need to change the localhost ? The following is the tree of the directory/repository... myflaskaws ├── requirements.txt ├── setup.py ├── static │ ├── assets │ │ ├── style.css │ └── images │ ├── no.png │ └── yes.png ├── templates │ ├── index.html │ ├──

问题 I'm running Django/Tastypie on a soon-to-be production environment, however I am noticing significant overhead using Apache vs. using the built-in dev server. Apache is MUCH slower. Here are non-scientific bandwidth tests using ab: Apache: $ ab -n 100 -c 50 https://www.mydomain.com/api/v1/clock/?format=json This is ApacheBench, Version 2.3 <$Revision: 655654 $> Copyright 1996 Adam Twiss, Zeus Technology Ltd, http://www.zeustech.net/ Licensed to The Apache Software Foundation, http://www

问题 I cannot for the life of me figure of why this flask application I'm trying to launch is not working. I am running it on a $5 Digital Ocean droplet. Here's (hopefully) everything you need to know about it: Directory layout (contained within /var/www/ ): FlaskApp FlaskApp __init__.py static templates venv flaskapp.wsgi __init__.py : from flask import Flask app = Flask(__name__) @app.route("/") def hello(): return "yay it worked" if __name__ == "__main__": app.run() flaskapp.wsgi : #!/usr/bin