word

In my project I'd like to open iOS built-in Dictionary to find word meaning, or even better, get the meaning of the word directly in my app. At the moment I found how to check a string is spelled correctly using UITextChecker func wordIsReal(word: String) -> Bool { let checker = UITextChecker() let range = NSMakeRange(0, count(word)) let misspelledRange = checker.rangeOfMisspelledWordInString(word, range: range, startingAt: 0, wrap: false, language: "en") return misspelledRange.location == NSNotFound } RiccardoCh I found the solution for Object-C : if ([UIReferenceLibraryViewController

I am trying to build a tool that allow people to get word or a phrase (on select), the select part is done but not the word part. I need to be able to get the current word when someone click on a word, and i found this solution get word click in paragraphs unfortunately, this code change all the words and add a <span> for every words, which causes an issue on my side since i cannot add html tags in the text (css file can be imported or added dynamically) is there's a better way to accomplish this, if possible? EX: Lorem ipsum dolor sit amet, consectetur adipiscing elit. Donec auctor ante sit

What's the best way to slice the last word from a block of text? I can think of Split it to a list (by spaces) and removing the last item, then reconcatenating the list. Use a regular expression to replace the last word. I'm currently taking approach #1, but I don't know how to concatenate the list... content = content[position-1:position+249] # Content words = string.split(content, ' ') words = words[len[words] -1] # Cut of the last word Any code examples are much appreciated. Actually you don't need to split all words. You can split you text by last space symbol into two parts using rsplit .

很多情况下，软件开发者需要从数据库读取数据，然后将数据动态填充到手工预先准备好的Word模板文档里，这对于大批量生成拥有相同格式排版的正式文件非常有用，这个功能应用PageOffice的基本动态填充功能即可实现。但若是用户想动态生成一个没有固定模版的公文时，换句话说，没有办法事先准备一个固定格式的模板时，就需要开发人员在后台用代码实现Word文档的从零到图文并茂的动态生成功能了。这里的“零”指的是Word空白文档。 　　那如何实现Word文档的从无到有呢，下面就把利用PageOffice实现这一功能的过程介绍一下。例如，想生成一个Word文档，里面的内容为：标题（粗体、黑体、字体大小为20、居中显示）、第一段内容（内容（略）、字体倾斜、字体大小为10、中文“楷体”、英文“Times New Roman”、红色、最小行间距、左对齐、首行缩进）、第二段内容（内容（略）、字体大小为12、黑体、1.5倍行间距、左对齐、首行缩进）、第三段内容（内容（略）、字体大小为14、华文彩云、2倍行间距、左对齐、首行缩进）、第四段内容插入一张图片。 　　1. 百度一下PageOffice，从官网下载PageOffice for Java的开发包； 　　2. 拷贝“集成文件”文件夹中的 lib 文件夹覆盖到您自己 Web 项目中 WEB-INF 目录下； 　　3. 打开“集成文件”文件夹中的 web

在Java应用系统中，我们经常需要配置文件来定制系统行为，这些配置文件可能包括：类路径下的文件和文件夹、非类路径下的绝对路径和相对路径的文件和文件夹，在分布式环境中，还需要通过HTTP从统一集中的Web服务器中获得配置信息，如何对这些配置信息进行自动加载并实时检测变化呢？ Java分布式中文分词组件 - word分词 已经实现了这个功能，我们看看是如何实现的： package org.apdplat.word.util; import java.io.BufferedReader; import java.io.File; import java.io.FileInputStream; import java.io.IOException; import java.io.InputStream; import java.io.InputStreamReader; import java.net.MalformedURLException; import java.net.URL; import java.nio.file.FileVisitResult; import java.nio.file.Files; import java.nio.file.Path; import java.nio.file.Paths; import java.nio.file

word分词是一个Java实现的分布式中文分词组件 1、下载 http://luke.googlecode.com/files/lukeall-4.0.0-ALPHA.jar （国内不能访问） 2、下载并解压 Java中文分词组件word-1.0-bin.zip 3、将解压后的 Java中文分词组件word-1.0-bin/word-1.0 文件夹里面的4个jar包解压到当前文件夹，用压缩解压工具如winrar打开lukeall-4.0.0-ALPHA.jar，将当前文件夹里面除了.jar、.bat、.html文件外的其他所有文件拖到lukeall-4.0.0-ALPHA.jar里面 4、执行命令 java -jar lukeall-4.0.0-ALPHA.jar 启动luke，在Search选项卡的Analysis里面就可以选择 org.apdplat.word.lucene.ChineseWordAnalyzer 分词器了 5、在Plugins选项卡的Available analyzers found on the current classpath里面也 可以选择 org.apdplat.word.lucene.ChineseWordAnalyzer 分词器 下载已经集成好的Luke插件： lukeall-4.0.0-ALPHA-with-word-1.0.jar

I have a table with a varchar(255) field. I want to get (via a query, function, or SP) the number of occurences of each word in a group of rows from this table. If there are 2 rows with these fields: "I like to eat bananas" "I don't like to eat like a monkey" I want to get word | count() --------------- like 3 eat 2 to 2 i 2 a 1 Any idea? I am using MySQL 5.2. Gabriel Rodriguez @Elad Meidar, I like your question and I found a solution: SELECT SUM(total_count) as total, value FROM ( SELECT count(*) AS total_count, REPLACE(REPLACE(REPLACE(x.value,'?',''),'.',''),'!','') as value FROM ( SELECT

Does Javascript have a built-in function to see if a word is present in a string? I'm not looking for something like indexOf() , but rather: find_word('test', 'this is a test.') -> true find_word('test', 'this is a test') -> true find_word('test', 'I am testing this out') -> false find_word('test', 'test this out please') -> true find_word('test', 'attest to that if you would') -> false Essentially, I'd like to know if my word appears, but not as part of another word. It wouldn't be too hard to implement manually, but I figured I'd ask to see if there's already a built-in function like this,