word-frequency

问题 Is it possible to identify distinct words and a count for each, from fields containing text strings in Postgres? 回答1: Something like this? SELECT some_pk, regexp_split_to_table(some_column, '\s') as word FROM some_table Getting the distinct words is easy then: SELECT DISTINCT word FROM ( SELECT regexp_split_to_table(some_column, '\s') as word FROM some_table ) t or getting the count for each word: SELECT word, count(*) FROM ( SELECT regexp_split_to_table(some_column, '\s') as word FROM some

问题 Input: A positive integer K and a big text. The text can actually be viewed as word sequence. So we don't have to worry about how to break down it into word sequence. Output: The most frequent K words in the text. My thinking is like this. use a Hash table to record all words' frequency while traverse the whole word sequence. In this phase, the key is "word" and the value is "word-frequency". This takes O(n) time. sort the (word, word-frequency) pair; and the key is "word-frequency". This

问题 I have recently discovered the Vim Tip n° 1531 (Word frequency statistics for a file). As suggested I put the following code in my .vimrc function! WordFrequency() range let all = split(join(getline(a:firstline, a:lastline)), '\A\+') let frequencies = {} for word in all let frequencies[word] = get(frequencies, word, 0) + 1 endfor new setlocal buftype=nofile bufhidden=hide noswapfile tabstop=20 for [key,value] in items(frequencies) call append('$', key."\t".value) endfor sort i endfunction

问题 I'm trying to find the frequency of letters without the Counter.And the code will output a dictionary form of result. And what I have done so far is to make the program count the word frequencies but not the letter/character frequencies. If anyone could point out my mistakes in this code that would be wonderful. Thank you. It supposed to look like this: {'a':2,'b':1,'c':1,'d':1,'z':1} **but this is what I am actually getting: {'abc':1,'az':1,'ed':1} **my code is below word_list=['abc','az',

问题 Given a .txt files with space-separated words such as: But where is Esope the holly Bastard But where is 생 지 옥 이 군 지 옥 이 지 옥 지 我 是 你 的 爸 爸 ！ 爸 爸 ！ ！ ！ 你 不 會 的 ！ And the Awk function : cat /pathway/to/your/file.txt | tr ' ' '\n' | sort | uniq -c | awk '{print $2" "$1}' I get the following output in my console which is invalid for korean words (valid for english and Chinese space-separated words) 생 16 Bastard 1 But 2 Esope 1 holly 1 is 2 the 1 where 2 不 1 你 2 我 1 是 1 會 1 爸 4 的 2 How to get it

问题 I'm working on a homework problem which requires me to read in words from an input file, and an integer k. The solution needs to print out a list of words and their frequencies, ranging from the most frequent to the k-th most frequent. If the number of unique words is smaller than k then only output that number of words. This would have been cake with containers like map, but the problem constrains me to be able to use vectors and strings only and no other STL containers. I'm stuck at the

问题 I have a column in my dataframe as follows Col1 ---------------------------------------------------------------------------- Center for Animal Control, Division of Hypertension, Department of Medicine Department of Surgery, Division of Primary Care, Center for Animal Control Department of Internal Medicine, Division of Hypertension, Center for Animal Control How do I count the number of strings that occur that is separated by a comma, in other words what I am trying to accomplish is something

问题 I am trying to find the most frequent words in the text field of an indexed document using Solr 4.10 . I created a PDF document from a text file with some text and posted it to Solr using post.jar and when queried based on its id it gives me pdf contents which are shown below and all meta-data of the document. <arr name="text"> <str>sample1</str> <str/> <str>application/pdf</str> <str> sample1 sample1.txt cook cook1 book1 book1 book2 nook1 nook1 nook2 nook2 two three four Page 1 </str> </arr>

问题 I have a dictionary like below: [{'mississippi': 1, 'worth': 1, 'reading': 1}, {'commonplace': 1, 'river': 1, 'contrary': 1, 'ways': 1, 'remarkable': 1}, {'considering': 1, 'missouri': 1, 'main': 1, 'branch': 1, 'longest': 1, 'river': 1, 'world--four': 1}, {'seems': 1, 'safe': 1, 'crookedest': 1, 'river': 1, 'part': 1, 'journey': 1, 'uses': 1, 'cover': 1, 'ground': 1, 'crow': 1, 'fly': 1, 'six': 1, 'seventy-five': 1}, {'discharges': 1, 'water': 1, 'st': 1}, {'lawrence': 1, 'twenty-five': 1,

问题 I have huge vector of words, and I want a vector with the unique words only, and the frequency for each word. I've already tried hist and histc but they are for numeric value. I know the function tabulate but it gives the words some ' (e.g this turns to 'this'). If you have any idea how to do it MATLAB it would be great. thanks 回答1: You were on the right track! Just use unique first to prepare the numeric input for hist . The trick is that the word occurence ids returned by unique can be used