while-loop

c++ while loop doesn't exit on false condition [closed]

时间秒杀一切 提交于 2019-12-24 11:14:19
问题 This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center. Closed 7 years ago . I'm having a problem in my code that results in a run time error. To debug the code I've thrown in some cout statements to find the last location that

Running while($row = sqlsrv_fetch_array($result)) multiple times

旧城冷巷雨未停 提交于 2019-12-24 10:57:59
问题 I am retrieving a couple of tables from a MSSQL database, which I am then running through to obtain order information from. My code looks like this: while($row = sqlsrv_fetch_array($orderResult)) { ......code........ .................. while($statusRow = sqlsrv_fetch_array($statusResult)) { ....code.... } ....code.... } Now my problem is that after the second loop runs through, it never runs again. And I need it to run every time the first loop runs. Is there anything I can do to reset that

Avoiding duplicating graph in tensorflow (LSTM model)

青春壹個敷衍的年華 提交于 2019-12-24 10:39:58
问题 I have the following simplified code (actually, unrolled LSTM model): def func(a, b): with tf.variable_scope('name'): res = tf.add(a, b) print(res.name) return res func(tf.constant(10), tf.constant(20)) Whenever I run the last line, it seems that it changes the graph. But I don't want the graph changes. Actually my code is different and is a neural network model but it is too huge, so I've added the above code. I want to call the func without changing the graph of model but it changes. I read

Controlling prompt for command line

若如初见. 提交于 2019-12-24 09:43:58
问题 I've made udp based client and server sample programs with C. My codes are followings [Server] #include <stdio.h> #include <string.h> #include <errno.h> #include <sys/types.h> #include <sys/socket.h> #include <netinet/in.h> #include <netdb.h> #include <arpa/inet.h> int printerror2(char func[], int errnum) { printf("%s error = %d:%s\n", func, errnum, strerror(errnum)); perror(func); return errnum; } int printerror(char func[]) { return printerror2(func, errno); } int main(int argc, char *argv[

How to read unknown number of inputs?

允我心安 提交于 2019-12-24 08:58:47
问题 I am learning C++ using the book C++ Primer. In Section 1.4.3 , the following example code about reading the unknown number of inputs is given. #include <iostream> int main() { int sum = 0, value = 0; // read until end-of-file, calculating a running total of all values read while (std::cin >> value) sum += value; // equivalent to sum = sum + value std::cout << "Sum is: " << sum << std::endl; return 0; } According to the book, if we give an input of 3 4 5 6 , the output will be Sum is: 18 But

Parsing a While Loop in Bison

こ雲淡風輕ζ 提交于 2019-12-24 08:42:33
问题 What is the best way to implement a simple while loop in Bison? If it makes a difference, I am using C, but I can use C++ as well. 回答1: What you're asking doesn't really fit into a Stack Overflow answer. It's pretty detailed, and many books have been written about it. The basic answer is that you don't implement while loops in Bison. Bison is not a language in that sense. Bison builds a parser from a grammar and actions that are associate with rules in that grammar. A parser is a pushdown

Parsing a While Loop in Bison

跟風遠走 提交于 2019-12-24 08:40:02
问题 What is the best way to implement a simple while loop in Bison? If it makes a difference, I am using C, but I can use C++ as well. 回答1: What you're asking doesn't really fit into a Stack Overflow answer. It's pretty detailed, and many books have been written about it. The basic answer is that you don't implement while loops in Bison. Bison is not a language in that sense. Bison builds a parser from a grammar and actions that are associate with rules in that grammar. A parser is a pushdown

Binary print not working in C

馋奶兔 提交于 2019-12-24 08:34:44
问题 I'm trying to print binary using bit mask of 32 bit in c but the binary representation is not getting printed in the if statement. unsigned int bit_mask = 2147483648; int decimal = 2; printf("\nBinary representation of 2: \n"); while(bit_mask > 0){ if((decimal & bit_mask) == 0) printf("0"); else printf("1"); bit_mask = bit_mask >> 1; } decimal = 255; printf("\n\nBinary representation of 255: \n"); while(bit_mask > 0){ if((decimal & bit_mask) == 0) printf("0"); else printf("1"); bit_mask = bit

Looping inside a while loop mysqli_fetch_array()

两盒软妹~` 提交于 2019-12-24 08:19:04
问题 I have the below working code to fetch images from database mysqli_fetch_array() and load the images into layout grid structure in Jquery Mobile 1.2.0. The layout grid structure of Jquery Mobile uses built-in styled grid/blocks limited to five columns, ui-block-a up to ui-block-e . Hence, I am ought to stick to JQM styles. NOTE: I am using four columns structure, ui-block-a to ui-block-d In order to load eight (8) images into the blocks and have them styled correctly, I have to use these

How to show/hide table row with jquery in while loop

℡╲_俬逩灬. 提交于 2019-12-24 07:59:40
问题 So I have a table generated from database with while loop. Data is displayed in rows. Point is that there are "hidden" rows with data available only on click (like show details). Basically I want something like this: http://www.transfercar.co.nz/ - if you click on the table row more data appears below (in new row). My code looks like this: while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)) { $display1=$display1+1; echo ' <tr class="tablerow"> <td>' . $row['id'] . '</td> <td><p class="state">