while-loop

问题 Closed. This question needs debugging details. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 5 years ago . Improve this question This my code i don't know what to do next I'm totally beginner int number = lb; while(number <= ub){ if (number % 7 == 0 && number % 15 == 0 && number % 17 == 0 && number % 30 != 0 ){ sum+= number; } number++; } System.out.println("Answer: " + sum); } } 回答1: You have to do

问题 I'm a beginner in python trying to create a RPS game where human is playing against a computer. The game is created such that it would be played over a number of determined rounds (best of 3 rounds). A draw is considered a point for each side. My problem is setting the while condition. Initially I did this: while (player_count + computer_count) != winning_score : where the game ends when all round are played. However there will be instances where not all rounds needs to be played and the

问题 I have the following task which is that: There may be up to ten teams. Parallel Arrays are used to store the team Names, as well as to keep track of the number of Wins, Overtime Losses, and Points. After the result for the last team is entered, the program outputs a summary of each team's record in the opposite order to which they were entered. Note: "W" is worth 2 points, "L" is worth 0 points, "O" is worth 1 point Sample input: 3 //Option number Toronto //phrase W //letters that loop in a

问题 This question has been asked and answered plenty of times before. However, I'm specifically asking for the substrings to be printed in the specific order by each letter as shown in the output. import java.util.*; public static void main(String[] args) { breakWordIntoPieces("ABIGWORD"); } public static void breakWordIntoPieces(String str) { if (str.length() > 1) // I'm skipping all substrings of less than 2 letters { List<String> fragments = breakWordIntoPiecesFromRightToLeft(str); for (String

问题 How is it that when I uncomment "//cout << current << endl;" in the code below, it works? #include <iostream> #include <float.h> using namespace std; int main() { char divider = 2; float power = 1; float number = 1; float current = number + power; cout.precision(1024); // Divide until rounded off while(current != number) { power /= divider; current = number + power; //cout << current << endl; } cout << power * divider << endl; cout << FLT_EPSILON << endl; } The code above prints: 1

问题 When put return in while loop the loop will stop How to fix it? ser = serial.Serial( port='COM5', baudrate = 9600, timeout=1) while 1: x=str(ser.readline()) x = re.findall("\d+\.\d+", x) x = float(x[0]) return(x) #loop stopped print(x) Could you please help me? 回答1: Simply take your x=str(ser.readline()) x = re.findall("\d+\.\d+", x) x = float(x[0]) return(x) #loop stopped put it into a function like def foo(ser): x=str(ser.readline()) x = re.findall("\d+\.\d+", x) x = float(x[0]) return(x)

问题 At the moment I'm currently re-writing a text-based program to have a GUI. One of the problems I am experiencing is that I want the program to wait until a certain condition is met. This condition can be met through the user clicking the "Walk" button until the player.walked attribute = 5. When using a text-based interface this is quite simple, use a while loop and inside have an input function. while (player.getWalked() < 5) { //wait for user input via terminal through the scanner. } However

问题 So I need to write a program which generates random numbers from 100 to 999, and the tricky part is that the digits in the number can't be the same. For example: 222 , 212 and so on are not allowed. So far, I have this: import random a = int (random.randint(1,9)) <-- first digit b = int (random.randint(0,9)) <-- second digit c = int (random.randint(0,9)) <-- third digit if (a != b and a != b and b != c): print a,b,c As you can see, I generate all three digits separately. I think it's easier

问题 So I need to write a program which generates random numbers from 100 to 999, and the tricky part is that the digits in the number can't be the same. For example: 222 , 212 and so on are not allowed. So far, I have this: import random a = int (random.randint(1,9)) <-- first digit b = int (random.randint(0,9)) <-- second digit c = int (random.randint(0,9)) <-- third digit if (a != b and a != b and b != c): print a,b,c As you can see, I generate all three digits separately. I think it's easier

问题 I write down a code which find out quotient after dividing two number but without using multiplication,division or mod operator. My code public int divide(int dividend, int divisor) { int diff=0,count=0; int fun_dividend=dividend; int fun_divisor=divisor; int abs_dividend=abs(dividend); int abs_divisor=abs(divisor); while(abs_dividend>=abs_divisor){ diff=abs_dividend-abs_divisor; abs_dividend=diff; count++; } if(fun_dividend<0 && fun_divisor<0){ return count; } else if(fun_divisor<0||fun