while-loop

This observation is not that important, because the time performance wasted on the loop statements will probably be much higher than the looping itself. But anyway, I will share it since I searched and couldn't find a topic about this. I always had this impression that pre-allocating the array I would loop, and then loop on it, would be better than looping directly on it, and decided to check it. The code would be to compare the efficiency between this two fors: disp('Pure for with column on statement:') tic for k=1:N end toc disp('Pure for with column declared before statement:') tic m=1:N;

I am trying to find the greatest common factor. I wrote a bad (operation intensive) algorithm that decrements the lower value by one, checks using % to see if it evenly divides both the numerator and denominator, if it does then it exits the program. However, my while loop is not using the and operator, and thus once the numerator is divisible it stops, even though its not the correct answer. The numbers I am using are 54 and 42, the correct GCD (greatest common denominator) is 6. #heres a simple algorithm to find the greatest common denominator: iterations = 0; #used to calculate number of

Looks like while( condition ) { //do stuff } is completely equivalent to for( ; condition; ) { //do stuff } Is there any reason to use the latter instead of the former? There's no good reason as far as I know. You're intentionally misleading people by using a for-loop that doesn't increment anything. Update: Based on the OP's comment to the question, I can speculate on how you might see such a construct in real code. I've seen (and used) this before: lots::of::namespaces::container::iterator iter = foo.begin(); for (; iter != foo.end(); ++iter) { // do stuff } But that's as far as I'll go with

I've recently read this page about strange C snippet codes. Most of them was understandable. But I can't understand this one: switch(c & 3) while((c -= 4) >= 0){ foo(); case 3: foo(); case 2: foo(); case 1: foo(); case 0: } Can anyone please help me out what logic is behind of this code? And how does it work? The duff's device comment should explain the background well enough, so I ll try to explain this very case: The switch checks the last 2 bits of c, and jumps to the respective case-statement inside the while loop. The code below the case statement is also executed. Control then reaches

I am trying to write a little game, but have stuck on how to prompt the user if they want to play again and how to exit the loop if they don't want to play again... import java.util.Random; import java.util.Scanner; public class Guessinggame { public static void main(String[] args) { System.out.println("Welcome to guessing game! \n" + " You must guess a number between 1 and 100. "); while (true) { Random randomNumber = new Random(); Scanner g = new Scanner(System.in); int number = randomNumber.nextInt(100) + 1; int guess = 0; int numberOfGuesses = 0; while (guess != number){ System.out.print(

Once an exception is caught in this code, the menuSystem method is run, but once I go to input a number the programme closes and the "Build is successful" message is displayed. Is there any way to get back into the while loop once an exception has occured? public static void main(String[] args) { final UnitResults myUnit = new UnitResults(10, "Java"); int option = menuSystem(); try { while (option != 0) { final Scanner keyb = new Scanner(System.in); System.out.println(""); switch (option) { } } } catch (Exception InputMismachException) { System.out.println("\nPlease Enter a Valid Number\n");

This question already has an answer here: How do I break out of nested loops in Java? 35 answers I have the following code: int x = 100; //Or some other value while(x > 0) { for(int i = 5; i > 0; i++) { x = x-2; if(x == 0) break; } } However, this will only break the for loop. How can I have it so that it breaks both the for and the while loops? Cheers! You can use a labeled break, which redirects the execution to after the block marked by the label: OUTER: while(x > 0) { for(int i = 5; i > 0; i++) { x = x-2; if(x == 0) break OUTER; } } Although in that specific case, a simple break would work