while-loop

While loop PHP get_result not working

删除回忆录丶 提交于 2019-12-02 05:28:23
问题 I am trying to get rows from the database using MySQl prepared statements and get result. However this is not working. Please can someone see where I am going wrong? I have been trying solutions for hours but I can't get it to work. The page just doesn't load as if the query has failed. $tag = trim($_GET['tag']); $stmt = $mysqli->prepare('SELECT posts.* FROM tags JOIN posts ON posts.id = tags.post_id WHERE tag = ?'); $stmt->bind_param('s', $tag); $stmt->execute(); $stmt->store_result();

How can I safely loop until there is nothing more to do without using a “placeholder” while conditon?

给你一囗甜甜゛ 提交于 2019-12-02 05:18:41
In order to call my Web API method until no more data is returned (I'm fetching it in batches, to keep each result set small, due to the 98-lb-weakling persona of the client (Windows CE handheld device)), I'm using this code: while (moreRecordsExist) { redemptionsList.redemptions.Clear(); string uri = String.Format("http://platypus:28642/api/Redemptions/{0}/{1}", lastIdFetched, RECORDS_TO_FETCH); var webRequest = (HttpWebRequest)WebRequest.Create(uri); webRequest.Method = "GET"; using (var webResponse = (HttpWebResponse)webRequest.GetResponse()) { if (webResponse.StatusCode == HttpStatusCode

How to end a while Loop via user input

社会主义新天地 提交于 2019-12-02 05:13:46
问题 package cst150zzhw4_worst; import java.util.Scanner; public class CST150zzHW4_worst { public static void main(String[] args) { //Initialize Variables double length; // length of room double width; // Width of room double price_per_sqyd; // Total carpet needed price double price_for_padding; // Price for padding double price_for_installation; // Price for installation String input; // User's input to stop or reset program double final_price; // The actual final price boolean repeat = true; //

Cin loop never terminating

被刻印的时光 ゝ 提交于 2019-12-02 05:03:38
I'm having trouble getting my cin loop to terminate in my program. My program uses Linux redirection to read in input from the file hw07data, the data file look like this: 100 20 50 100 40 -1 A34F 90 15 50 99 32 -1 N12O 80 15 34 90 22 -1 The first portion is the total points for the class, the next lines are the students ID number followed by their scores, all terminated by -1. My issue: my while loop never terminates when i run the command ./a.out < hw07data , could anyone look over my code and give me some hints? I dont want the answer, as this is homework, i just need some guidance. Thanks!

How do I fill an array inside a while loop and get new scope each iteration?

半城伤御伤魂 提交于 2019-12-02 04:29:16
The problem is that I get only the last value comming from the Table. I think its because I am building the array while referencing its values to the same object, and it keeps changing. I know while loop doesnt create a new scope for each iteration which IS the problem. What's the best way to get a new scope for each iteration? Code: $namesArray= array(); while ($row=mysql_fetch_array($result)) { $nameAndCode->code = $row['country_code2']; $nameAndCode->name = $row['country_name']; array_push($namesArray,$nameAndCode); } return $namesArray; You need to create a new object on each iteration:

Unreachable statement error using while loop in java [duplicate]

佐手、 提交于 2019-12-02 04:25:32
问题 This question already has answers here : Closed 6 years ago . Possible Duplicate: Why is this code giving an “Unreachable Statement” error? This seems very easy question, I found this question in one book. If anyone help me to figure out why I'm getting error. do { System.out.print("inside do"); } while (false); while (false) { // error System.out.print("inside while"); } System.out.print("outside"); I thought, and according to me, output should be inside dooutside . But, it is showing

Loop Issue Counting Year In PHP

不羁岁月 提交于 2019-12-02 04:15:36
问题 I have created a loop which will display date 2004 to 2014 in a formatted way. But the problem is, it is showing 204 instead of 2004 and continue this till 209.. So, how to show those year in formatted way, like 2004,2005,2006 etc. Here is the code i have created, tell me where to fix: <?php $yr = 4; while ($yr <= 14) { $x = 1; while ($x <= 31) { echo "$x Jan 20$yr<br>"; $x++; } $x = 1; while ($x <= 31) { echo "$x Feb 20$yr<br>"; $x++; } $x = 1; while ($x <= 31) { echo "$x Mar 20$yr<br>"; $x+

python repeat program while true [duplicate]

可紊 提交于 2019-12-02 04:09:05
This question already has an answer here: Asking the user for input until they give a valid response 18 answers How to let a raw_input repeat until I want to quit? 4 answers I am attempting to make my program repeat when the user inputs y/n, however I am confused on how to use a while true with this type of input, below is some code. again = input("Would you like to play again? enter y/n: ") if again == "n": print ("Thanks for Playing!") quit if again == "y": print ("Lets play again..") ???? Also, I want to do an else statement if the user enters in a different character, but am unsure on how

Python “while x:” statement [duplicate]

删除回忆录丶 提交于 2019-12-02 04:08:07
This question already has an answer here: Python evaluates 0 as False 4 answers What is Truthy and Falsy? How is it different from True and False? 4 answers Why the following while loop is exited when x reaches 0 ? x = 1 while x: print(x) x -= 1 It prints only 1 . Shouldn't the while statement be something like: while x "is something": and not just while x: ? Because bool(0) => False , and bool(x) for x!=0 => True , so it's like saying while x!=0 or while x>0 in your case. In boolean, none zero value means 'true' and 0 means 'false'. The code reaches the argument while(0) or while(false) and

For Loop in JavaScript - Lottery Website

心已入冬 提交于 2019-12-02 04:06:27
I am trying to turn this code into a correct for loop statement, so that I can save my repetitions. I have tried my best to get it done, but I just don't know how I can write it correctly: function myProg() { var luckyNumber = 3; var luckyNumber2 = 5; var luckyNumber3 = 8; var firstInput = document.luckForm.numberBox.value; var secondInput = document.luckForm.numberBox2.value; var thirdInput = document.luckForm.numberBox3.value; var temp = ''; if (firstInput == luckyNumber && secondInput == luckyNumber2 && thirdInput == luckyNumber3 || firstInput == luckyNumber && secondInput == luckyNumber3 &