wchar-t

I am reading the book: C: In a Nutshell , and after reading the section Character Sets , which talks about wide characters, I wrote this program: #include <stdio.h> #include <stddef.h> #include <wchar.h> int main() { wchar_t wc = '\x3b1'; wprintf(L"%lc\n", wc); return 0; } I then compiled it using gcc, but gcc gave me this warning: main.c:7:15: warning: hex escape sequence out of range [enabled by default] And the program does not output the character α (whose unicode is U+03B1), which is what I wanted it to do. How do I change the program to print the character α? This works for me #include

char cmd[40]; driver = FuncGetDrive(driver); sprintf_s(cmd, "%c:\\test.exe", driver); I cannot use cmd in sei.lpFile = cmad; so, how to convert char array to wchar_t array ? Traveling Tech Guy From MSDN : #include <iostream> #include <stdlib.h> #include <string> using namespace std; using namespace System; int main() { char *orig = "Hello, World!"; cout << orig << " (char *)" << endl; // Convert to a wchar_t* size_t origsize = strlen(orig) + 1; const size_t newsize = 100; size_t convertedChars = 0; wchar_t wcstring[newsize]; mbstowcs_s(&convertedChars, wcstring, origsize, orig, _TRUNCATE);

i'm currently working on a C++ project in which I need to display some extended characters (wchar_t). The main problem is that, even if it works fine in C (using wprintf ), it doesn't work in c++ using mvwaddwstr or waddwstr . Of course, i've set the locale like that: setlocale(LC_ALL, ""); , and nothing is displayed. Does someone got this problem before, or has an idea about that? Thanks. Here is the code: struct charMap { int x; int y; wchar_t value }; int i, x, y; wchar_t str[2]; struct charMap _charMap[2] = { {0,0,9474} {29, 29, 9474} }; initscr(); setlocale(LC_ALL, ""); for (y = 0 ; y <

I changed my class to use std::string (based on the answer I got here but a function I have returns wchar_t *. How do I convert it to std::string? I tried this: std::string test = args.OptionArg(); but it says error C2440: 'initializing' : cannot convert from 'wchar_t *' to 'std::basic_string<_Elem,_Traits,_Ax>' You could just use wstring and keep everything in Unicode wstring ws( args.OptionArg() ); string test( ws.begin(), ws.end() ); You can convert a wide char string to an ASCII string using the following function: #include <locale> #include <sstream> #include <string> std::string ToNarrow

I'm getting an error in my C++ code that I can't quite make sense of. The stripped down code bits are here: RS232Handle=OpenRS232("COM1", 9600); HANDLE OpenRS232(const char* ComName, DWORD BaudRate) { ComHandle=CreateFile(ComName, GENERIC_READ|GENERIC_WRITE, 0, NULL, OPEN_EXISTING, FILE_ATTRIBUTE_NORMAL, NULL); } I get the following error: error: cannot convert 'const char*' to 'LPCWSTR {aka const wchar_t*}' for argument '1' to 'void* CreateFileW(LPCWSTR, DWORD, DWORD, LPSECURITY_ATTRIBUTES, DWORD, DWORD, HANDLE)' ComHandle=CreateFile(ComName, GENERIC_READ|GENERIC_WRITE, 0, NULL, OPEN_EXISTING

I am working on a project where I have many constant strings formed by concatenation (numbers, etc.). For example, I have a LOCATION macro that formats __FILE__ and __LINE__ into a string that I can use to know where I am in the code, when printing messages or errors: #define _STR(x) # x #define STR(x) _STR(x) #define LOCATION __FILE__ "(" STR(__LINE__) ")" So, this would format a location like "file.cpp(42)". The problem is when I try to convert the result to a wide-string: #define _WIDEN(x) L ## x #define WIDEN(x) _WIDEN(x) #define WLOCATION WIDEN(LOCATION) This works just fine with GCC, and