void

Is void a data type in the C programming language? If so, what type of values can it store? If we have int , float , char , etc., to store values, why is void needed? And what is the range of void? James Curran Void is considered a data type (for organizational purposes), but it is basically a keyword to use as a placeholder where you would put a data type, to represent "no data". Hence, you can declare a routine which does not return a value as: void MyRoutine(); But, you cannot declare a variable like this: void bad_variable; However, when used as a pointer, then it has a different meaning:

I am not sure what this means, whenever before you write a code, people say this public static void main(String[] args) { What does that mean? Sai Upadhyayula Here is a little bit detailed explanation on why main method is declared as public static void main(String[] args) Main method is the entry point of a Java program for the Java Virtual Machine(JVM). Let's say we have a class called Sample class Sample { static void fun() { System.out.println("Hello"); } } class Test { public static void main(String[] args) { Sample.fun(); } } This program will be executed after compilation as java Test .

An often used statement like (void)x; allows to suppress warnings about unused variable x . But if I try compiling the following, I get some results I don't quite understand: int main() { int x; (short)x; (void)x; (int)x; } Compiling this with g++, I get the following warnings: $ g++ test.cpp -Wall -Wextra -o test test.cpp: In function ‘int main()’: test.cpp:4:13: warning: statement has no effect [-Wunused-value] (short)x; ^ test.cpp:6:11: warning: statement has no effect [-Wunused-value] (int)x; ^ So I conclude that casting to void is very different from casting to any other types, be the

This question already has an answer here: Is it better to use C void arguments “void foo(void)” or not “void foo()”? [duplicate] 6 answers When a C function does not accept any arguments, does it have to be declared/defined with a "void" parameter by the language rules? PC-Lint seems to have problems when there's nothing at all in the argument-list, and I was wondering if it's something in the language syntax that I don't know about. Edit: I just found a duplicate (back-dupe? it came first) question, C void arguments , which has more answers and explanations. void means the function does not

What exactly is the difference between undefined and void 0 ? Which is preferred and why? The difference is that some browsers allow you to overwrite the value of undefined . However, void(anything) always returns real undefined . undefined = 1; console.log(!!undefined); //true console.log(!!void(0)); //false undefined has normal variable semantics that not even strict mode can fix and requires run-time look-up. It can be shadowed like any other variable, and the default global variable undefined is not read-only in ES3. void 0 is effectively a compile time bulletproof constant for undefined

The return type—the data type of the value returned by the method, or void if the method does not return a value. http://download.oracle.com/javase/tutorial/java/javaOO/methods.html Okay, then.. Here is my question: public class EnumTest { Day day; public EnumTest(Day day) { this.day = day; } public void tellItLikeItIs() { switch (day) { case MONDAY: System.out.println("Mondays are bad."); break; case FRIDAY: System.out.println("Fridays are better."); break; case SATURDAY: case SUNDAY: System.out.println("Weekends are best."); break; default: System.out.println("Midweek days are so-so.");