virtual

templates may not be ‘virtual’

强颜欢笑 提交于 2019-12-04 23:47:41
Given the code below, the compiler is showing a message pointing that error: templates may not be ‘virtual’ . Does anyone have a suggestion on how to solve the bug? template < class FOO_TYPE> class CFoo{ public: ... template < class BAR_TYPE > virtual void doSomething( const CBar<BAR_TYPE> &); // here's the error ... virtual ~CFoo(); protected: MyClass < FOO_TYPE > * m_pClass; }; template < class FOO_TYPE > template < class BAR_TYPE > void CFoo<FOO_TYPE>::doSomething( const CBar<BAR_TYPE> & refBar ){ ... } The easiest reason to see why this is illegal is by considering the vtable. Sure, that's

C++: Private virtual functions vs. pure virtual functions [duplicate]

北慕城南 提交于 2019-12-04 22:32:10
问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: Private virtual method in C++ If I understood correctly from this post (Private virtual method in C++), making a virtual function in a base class makes the derived classes able to override it. But it seems things stop there. But if the base class virtual function is pure, that forces the derived classes to implement the function. Hence, a pure (public) virtual function is merely an interface. I can see a benefit

Creating clone of an object not working with virtual base class

流过昼夜 提交于 2019-12-04 22:25:41
#include<iostream> using namespace std; class Something { public: int j; Something():j(20) {cout<<"Something initialized. j="<<j<<endl;} }; class Base { private: Base(const Base&) {} public: Base() {} virtual Base *clone() { return new Base(*this); } virtual void ID() { cout<<"BASE"<<endl; } }; class Derived : public Base { private: int id; Something *s; Derived(const Derived&) {} public: Derived():id(10) {cout<<"Called constructor and allocated id"<<endl;s=new Something();} ~Derived() {delete s;} virtual Base *clone() { return new Derived(*this); } virtual void ID() { cout<<"DERIVED id="<<id<

Virtual methods without body

我们两清 提交于 2019-12-04 22:22:47
I was looking at some code in an abstract class: public virtual void CountX(){} public virtual void DoCalculation() { ...code} Why should I declare an empty virtual method in an abstract class if it is not mandatory to override it in derived types? As @Adam told you, there are many cases in which it makes sense. When you create an abstract class, it's because you want to create a common interface for all classes deriving from that one; however, at that level of inheritance you won't have enough information to be able to create working code for that method. For example, if you create the class

【转】浅谈 React/Vue/Inferno 在 DOM Diff 算法上的异同

馋奶兔 提交于 2019-12-04 20:44:42
今天看了一篇慕课网茵风泳月老师的手记,搬运到自己的博客园来,方便以后查看。 原文地址:https://www.imooc.com/article/295545 一、引言 在现代的前端渲染框架中,Virtual DOM 几乎已经成了标配,通过这样一个缓冲层,我们已经能够实现对 Real DOM 的最少操作,在大家的广泛认知中,操作 DOM 是比较慢的,因此 Virtual DOM 可以实现应用程序的性能提升。 毫无疑问,Virtual DOM 不可能全量同步到 Real DOM,因为那样就违背了设计 Virtual DOM 的初衷,那么Virtual DOM 同步到 Real DOM 的操作就称之为 DOM Diff,顾名思义,计算两个 DOM Tree 之间的差异性,增量更新 Real DOM。更新动作的原则是,能复用的节点绝不删除重新创建。 不同框架对于 DOM Diff 的理解并不完全一致,但有一点可以达成共识:由于 DOM 本身是树形(Tree)结构,不同层级之间的节点(Node)没有必要对比,因为这可能会带来 O(N³) 的计算复杂度,很可能还不如直接操作 Real DOM 来的快。因此,狭义的 DOM Diff 算法,一般指的是同一层级兄弟节点的范围之内。 本文,我就对典型的几种 DOM Diff 实现进行简单的介绍,并分析潜在的陷阱

On Linux: We see following: Physical, Real, Swap, Virtual Memory - Which should we consider for sizing?

爷,独闯天下 提交于 2019-12-04 19:23:35
We use a Tool (Whats Up Gold) to monitor memory usage on a Linux Box. We see Memory usage (graphs) related to: Physical, Real, Swap, Virtual Memory and ALL Memory ( which is a average of all these ). 'The ALL' Memory graphs show low memory usage of about: 10%. But Physical memory shows as 95% used. Swap memory shows as 2% used. So, do i need more memory on this Linux Box? In other words should i go by: ALL Memory graph(which says memory situation is good) OR Physical Memory Graph (which says memory situation is bad). Real and Physical Physical memory is the amount of DRAM which is currently

Size of classes with virtual functions GCC/Xcode

此生再无相见时 提交于 2019-12-04 19:12:28
Can anyone explain to me what is going on here? First off, I think most programmers know that a class with a virtual function has a vtbl and thus has 4 extra bytes on the top of it. As far as I know, that's fairly standard. I've tested this and taken advantage of this fact before to do load in place from a binary file with patched vtbls. For the last 6 months, I've been working in Xcode and just recently came across the need to do some load in place stuff, so I was looking into patching vtbls again. Just to make sure my understanding was correct, I wrote a sample program. Here it is: class A {

C++ Overridden method not getting called

安稳与你 提交于 2019-12-04 18:48:38
问题 Shape.h namespace Graphics { class Shape { public: virtual void Render(Point point) {}; }; } Rect.h namespace Graphics { class Rect : public Shape { public: Rect(float x, float y); Rect(); void setSize(float x, float y); virtual void Render(Point point); private: float sizeX; float sizeY; }; } struct ShapePointPair { Shape shape; Point location; }; Used like this: std::vector<Graphics::ShapePointPair> theShapes = theSurface.getList(); for(int i = 0; i < theShapes.size(); i++) { theShapes[i]

virtual studio 插入 函数注释头 snippet方式

守給你的承諾、 提交于 2019-12-04 18:25:48
简介 以前通过一个插件就可以管理所有的函数,也可以通过snippet插入 参考链接 如何使用snippet https://blog.csdn.net/weixin_30278237/article/details/98262682 教程 https://blog.csdn.net/github_37687123/article/details/87982862 来源: https://www.cnblogs.com/eat-too-much/p/11877295.html

C++ Parent class calling a child virtual function

二次信任 提交于 2019-12-04 17:15:01
问题 I want a pure virtual parent class to call a child implementation of a function like so: class parent { public: void Read() { //read stuff } virtual void Process() = 0; parent() { Read(); Process(); } } class child : public parent { public: virtual void Process() { //process stuff } child() : parent() { } } int main() { child c; } This should work, but I get an unlinked error :/ This is using VC++ 2k3 Or shouldn't it work, am I wrong? 回答1: Title of the following article says it all: Never