uuid

Is python uuid1 sequential as timestamps?

微笑、不失礼 提交于 2019-11-29 09:27:25
Python docs states that uuid1 uses current time to form the uuid value. But I could not find a reference that ensures UUID1 is sequential. >>> import uuid >>> u1 = uuid.uuid1() >>> u2 = uuid.uuid1() >>> u1 < u2 True >>> But not always: >>> def test(n): ... old = uuid.uuid1() ... print old ... for x in range(n): ... new = uuid.uuid1() ... if old >= new: ... print "OOops" ... break ... old = new ... print new >>> test(1000000) fd4ae687-3619-11e1-8801-c82a1450e52f OOops 00000035-361a-11e1-bc9f-c82a1450e52f UUIDs Not Sequential No, standard UUIDs are not meant to be sequential. Apparently some

Foolproof way of differentiating String and UUID

假装没事ソ 提交于 2019-11-29 09:27:12
If I have a string "key:<String || UUID>" is there a way where I can extract the string and differentiate of the part after : is a string or a UUID? Example: in this key:863864947148451183L and key:1234 May be by using the size of a UUID or the number of bytes? The only foolproof way is to use UUID.fromString(yourString); It will return an java.lang.IllegalArgumentException: Invalid UUID string: "someString" Handle the exception. The javadoc explains the UUID format. Victor Using exceptions to replace logic is never a good option. In this case the use of the exception is also erroneous,

VAS授权接入开发者文档,全民共创VAS生态

不问归期 提交于 2019-11-29 07:27:26
在这里致敬所有开发者,我们正在改变整个世界! 用户可在第三方网页或APP中通过VAS授权机制,来获取用户基本信息和接收用户付款,进而实现业务逻辑,共创VAS生态。 VAS钱包的Scheme为vaswallet 申请授权接入 ​接入方需在vas钱包授权申请中填写上线的第三方应用相关信息,社区通过评审通过后会在APP中反馈接入情况。 其中授权回调域名配置规范为全域名,比如需要网页授权的域名为:错误! 超链接引用无效。http://www.vasblock.com/music.html 、 http://www.vasblock.com/login.html 都可以进行授权操作。但http://pay.vasblock.com 、 http://music.vasblock.com 、 http://vasblock.com无法进行授权操作。 如果是手机H5发起的授权操作,scheme请填写http或者https,并填写安全回调域名。 ​ 接入方申请通过后将获得uuid,accessToken,rsaPrivate,rsaPublic(可在DAPP接入申请记录点击“查看详情”进行查看,如有疑问请发送邮件至vas.github@outlook.com或在github上留言),作用将会在下面介绍。 授权登录流程分为四步: 1、第三方APP激活vaswallet; 2

default value of GUID in for a column in mysql

最后都变了- 提交于 2019-11-29 06:15:16
I want a column to default to a GUID, so if I am doing an insert and I don't explicitly set the value, I want it to default to a new GUID value. how can I do this? Being that UUID() isn't accepted as a DEFAULT constraint, you need to use a trigger. This one sets the value for the NEW_TABLE.uuid column: delimiter $$ CREATE DEFINER=`root`@`localhost` TRIGGER `example`.`newid` BEFORE INSERT ON `example`.`new_table` FOR EACH ROW BEGIN SET NEW.`uuid` = UUID(); END $$ pospi Previous answer is not quite right - you've got to be careful with triggers... they will actually overwrite any default value

Alternative to __uuidof in C

牧云@^-^@ 提交于 2019-11-29 06:11:48
I'm working with a C project that's using DirectX and I've run into a problem. Certain DX calls require a IID object, typically generated with __uuidof . One thing this is required for is creating a RenderTargetView. The DirectX samples/tutorials do this: ID3D11Texture2D* pBackBuffer = NULL; hr = g_pSwapChain->GetBuffer( 0, __uuidof( ID3D11Texture2D ), ( LPVOID* )&pBackBuffer ); When I try to call __uuidof in my C code, I get an compiler error: Error 19 error C4233: nonstandard extension used : '__uuidof' keyword only supported in C++, not C . DirectX has a C interface, so I imagine there must

通过复制创建虚拟机,无法联网的解决办法

﹥>﹥吖頭↗ 提交于 2019-11-29 05:39:18
vmware 下找不到ifcfg-eth0的问题 http://www.linuxdiyf.com/viewarticle.php?id=90924 在windowXP下安装了suse linux,在vmware下选择了host-only方式与主机通信。 使用host-only方式与主机通信,vmware使用的是VMware Network Adapter VMnet1虚拟网卡,查看该网卡的IP是 192.168.174.1。 在虚拟机下面的linux下遇到了一下几个问题: 1、找不大 eth0网卡,也就连不上网络。症状是ifconfig以后只现实lo,不显示eth0。 解决方法: ifconfig eth0 up。这样ifconfig以后就显示了eth0。 找到eth0以后,再运行ifconfig eth0 192.168.174.2 netmask 255.255.255.0。即可与主机通信。 2、经过上面步骤是找到了eth0,可是重启以后又没有了。 解决方法: cd /etc/sysconfig/network/ cp ifcfg-lo ifcfg-eth0 vim ifcfg-eth0 修改配置如下 IPADDR=192.168.174.2 NETMASK=255.255.255.0 NETWORK=192.168.174.0 BROADCAST=192.168.174

How can I generate a GUID in R?

流过昼夜 提交于 2019-11-29 05:33:46
How can I generate GUIDs and UUIDs in R? I would like to be able to generate GUIDs based on the hardware etc. of the machine running the rsession. As a fallback, however, I would be happy to create UUIDs that comply with rfc4122. Is there a package that can create GUIDs? Otherwise, does someone have some RFC4122 compatible UUID code lying about? The optimal choice for this now is the uuid package. It consists of one function ( UUIDgenerate ) that doesn't rely on R's internal random number generators and so doesn't suffer any consequences from using set.seed in a session as @thelatemail's

Inserting a hard-coded UUID via CQLsh (Cassandra)

冷暖自知 提交于 2019-11-29 05:24:00
Would like to populate some static test data via a CQLsh script. This doesn't work: (device_id is UUID) insert into devices (device_id, geohash,name, external_identifier, measures, tags) values ('c37d661d-7e61-49ea-96a5-68c34e83db3a','9q9p3yyrn1', 'Acme1', '936', {'aparPower','actPower','actEnergy'},{'make':'Acme'}); Bad Request: Invalid STRING constant (c37d661d-7e61-49ea-96a5-68c34e83db3a) for device_id of type uuid I can't seem to find any CQL function to convert to proper type. Do I need to do this from a python script? Thanks, Chris You shouldn't put the quotes around the UUID to stop it

在PHP中使用UUID扩展的函数

纵然是瞬间 提交于 2019-11-29 03:57:22
环境: CentOS Linux release 7.7.1908 (Core) PHP 7.3.11 UUID Extention 1.0.4 感觉上PHP对UUID的支持似乎不是很上心,PECL中的UUID扩展仅仅是对libuuid的打包,并没有像其他语言那样直接提供完整的UUID实现。由于libuuid仅仅提供了版本1和版本4的UUID,所以……,开心一点,这两个就够用了。 uuid_create( [int $uuid_type = UUID_TYPE_DEFAULT] ) : string $uuid_type   如下常量之一:      UUID_TYPE_DEFAULT // 0      UUID_TYPE_TIME // 1      UUID_TYPE_DCE // 4      UUID_TYPE_NAME // 1      UUID_TYPE_RANDOM // 4   libuuid提供了UUID版本1和版本4的实现,也只定义了 UUID_TYPE_DCE_TIME 和 UUID_TYPE_DCE_RANDOM 两个常量。PHP的UUID扩展中,常量是通过映射libuuid的常量定义的。所以,虽然扩展中根据UUID标准定义了4个常量名,但对于当前版本的libuuid,也只能映射到两个常量。 UUID_TYPE_TIME 映射为libuuid的常量

GUID to ByteArray

ぐ巨炮叔叔 提交于 2019-11-29 02:56:30
I just wrote this code to convert a GUID into a byte array. Can anyone shoot any holes in it or suggest something better? public static byte[] getGuidAsByteArray(){ UUID uuid = UUID.randomUUID(); long longOne = uuid.getMostSignificantBits(); long longTwo = uuid.getLeastSignificantBits(); return new byte[] { (byte)(longOne >>> 56), (byte)(longOne >>> 48), (byte)(longOne >>> 40), (byte)(longOne >>> 32), (byte)(longOne >>> 24), (byte)(longOne >>> 16), (byte)(longOne >>> 8), (byte) longOne, (byte)(longTwo >>> 56), (byte)(longTwo >>> 48), (byte)(longTwo >>> 40), (byte)(longTwo >>> 32), (byte)