uuid | 易学教程

Linux基础学习-网络管理

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1 启动网络管理服务和开机自启动在rhel7中网路管理相关命令 nmcli , nmtui , nmtui-edit , nm-connection-editor 服务启动描述 systemctl start NetworkManager 启动服务 systemctl restart NetworkManager 重启服务 systemctl stop NetworkManager 停止服务 systemctl enable NetworkManager 开机自启动服务 systemctl disable NetworkManager 取消开机自启动 [root@qdlinux ~]# systemctl disable NetworkManager Removed symlink /etc/systemd/system/multi-user.target.wants/NetworkManager.service. Removed symlink /etc/systemd/system/dbus-org.freedesktop.NetworkManager.service. Removed symlink /etc/systemd/system/dbus-org.freedesktop.nm-dispatcher.service. [root@qdlinux ~]#

springBoot jpa uuid生成策略

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实体类 import org.hibernate.annotations.GenericGenerator; import javax.persistence.*; @Entity @Table(name = "Test") @GenericGenerator(name = "jpa-uuid", strategy = "uuid") public class Test{ @Id @GeneratedValue(generator = "jpa-uuid") @Column(length = 32) private String uid; private String name; public Test(){ } public String getUid() { return uid; } public void setUid(String uid) { this.uid = uid; } public String getName() { return name; } public void setName(String name) { this.name = name; } } 　　文章来源: springBoot jpa uuid生成策略

javascript-hashchange事件和历史状态管理

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hashchange事件，可以监听URL参数（#后面的字符串）什么时候发生变化。 <!DOCTYPE html> < html lang = "en" > < head > < meta charset = "UTF-8" > < meta name = "viewport" content = "width=device-width, initial-scale=1.0" > < meta http-equiv = "X-UA-Compatible" content = "ie=edge" > < title > Document </ title > < script src = "EventUtil.js" > </ script > < script > EventUtil.addHandler(window, 'load' , function () { var form = document.forms[ 0 ] var elements = form.elements var mybutton = elements[ 'createBtn' ] var div = document.getElementById( 'uuid' ) var data = {} EventUtil.addHandler(mybutton, 'click' , function

生成32位大写的随机唯一字符

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一、使用工具类UUID 　　使用工具类UUID生成随机的唯一字符，并且可以转换成适合的格式。 1 package com.learn; 2 3 import org.junit.Test; 4 5 import java.util.UUID; 6 7 /** 8 * 创建32位唯一字符 9 * 10 * @author zhongtao on 2018/5/15 11 */ 12 public class BuildUUID { 13 14 /** 15 * 生成唯一字符带有 - 符号 16 */ 17 @Test 18 public void test1() { 19 String uuid = UUID.randomUUID().toString(); 20 System.out.println(uuid); 21 //d099ed23-8af5-41fc-8e20-76ed66fe3889 22 } 23 24 /** 25 * 替换-符号，并将字母转换为大写 26 */ 27 @Test 28 public void test2() { 29 String uuid = UUID.randomUUID().toString().replace("-", "").toUpperCase(); 30 System.out.println(uuid); 31 /

java类uuid源码分析

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通用唯一识别码（英语：Universally Unique Identifier，简称UUID）是一种软件建构的标准，亦为自由软件基金会组织在分散式计算环境领域的一部份。 UUID的目的，是让分散式系统中的所有元素，都能有唯一的辨识信息，而不需要通过中央控制端来做辨识信息的指定。如此一来，每个人都可以创建不与其它人冲突的UUID。一组UUID，是由一串16位组（亦称128位）的16进位数字所构成，是故UUID理论上的总数为216 x 8=2128，约等于3.4 x 1038。也就是说若每纳秒产生1兆个UUID，要花100亿年才会将所有UUID用完。所以无需考虑它的重复性。 UUID的标准型式包含32个16进位数字，以连字号分为五段，形式为8-4-4-4-12的32个字符，加上“-”一共是 36 λ ，所以咱们可以先取出uuid，再把“-”去掉。 import java . util . UUID ; import org . apache . commons . lang3 . RandomStringUtils ; public class RandomUtils { public RandomUtils () { } public static String generateTicket () { String ticket = UUID . randomUUID ().

JAVA生成64，32位UUID密钥

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/** * 生成lenght位的密钥 * @param lenght 可变长度的密钥 * @param ma 是否转换大小写，true大写，false小写 * @return */ static Random random = new Random(); static String KeyValue_lenght(int lenght, boolean... ma) { //定义一个字符串（A-Z，a-z，0-9）即62位； String str = "zxcvbnmlkjhgfdsaqwertyuiopQWERTYUIOPASDFGHJKLZXCVBNM1234567890"; //由Random生成随机数 StringBuffer sb = new StringBuffer(); //长度为几就循环几次 for (int i = 0; i < lenght; ++i) { //产生0-61的数字 int number = random.nextInt(62); //将产生的数字通过length次承载到sb中 sb.append(str.charAt(number)); } //将承载的字符转换成字符串 return ma.length != 0 ? ma[0] ? sb.toString().toUpperCase() : sb.toString().toLowerCase()

Is there any way to generate the same UUID from a String

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I am wondering if there is a way to generate the same UUID based on a String. I tried with UUID, it looks like it does not provide this feature. You can use UUID this way to get always the same UUID for your input String: String aString="JUST_A_TEST_STRING"; String result = UUID.nameUUIDFromBytes(aString.getBytes()).toString(); 来源： https://stackoverflow.com/questions/29059530/is-there-any-way-to-generate-the-same-uuid-from-a-string

Output UUID in Go as a short string

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Is there a built in way, or reasonably standard package that allows you to convert a standard UUID into a short string that would enable shorter URL's? I.e. taking advantage of using a larger range of characters such as [A-Za-z0-9] to output a shorter string. I know we can use base64 to encode the bytes, as follows, but I'm after something that creates a string that looks like a "word", i.e. no + and / : id = base64.StdEncoding.EncodeToString(myUuid.Bytes()) A universally unique identifier (UUID) is a 128-bit value, which is 16 bytes. For human-readable display, many systems use a canonical

How to generate UUID with angular 2?

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I'm using Angular 2 for a signup form: first name, last name, email and password. After submit, the data is being stored via API call in a database (nodeJs and mongo) and generates a JWT Token which is sent back to the client. Now I should add/generate an UUID (Universal Unique Identifier). As I never have done this kind of feature before, I need an approach and idea/solution how to achieve this... would the JWT Token be a kind of alternative to UUID? If yes, this would be enough. Otherwise I would prefer to avoid any big changes on the form or its functionality. I Have been searching, but

I need to generate uuid for my rails application. What are the options(gems) I have? [duplicate]

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This question already has an answer here: Generating Guids in Ruby 10 answers I use Rails 3.0.20 and ruby 1.8.7 (2011-06-30 patchlevel 352) Please suggest me the best plugin to generate guid. There are plenty of options, I recommend not to add additional dependencies and use SecureRandom which is builtin: SecureRandom.uuid #=> "1ca71cd6-08c4-4855-9381-2f41aeffe59c" See other possible formats here . The first thing I would suggest is that please upgrade your ruby and rails version. A very good way of generating guid is SecureRandom , which is a ruby module. With easy usage. require