uuid

How to create a GUID/UUID using iOS

由 流过昼夜 提交于 2019-12-17 02:03:44
问题 I want to be able to create a GUID/UUID on the iPhone and iPad. The intention is to be able to create keys for distributed data that are all unique. Is there a way to do this with the iOS SDK? 回答1: [[UIDevice currentDevice] uniqueIdentifier] Returns the Unique ID of your iPhone. EDIT: -[UIDevice uniqueIdentifier] is now deprecated and apps are being rejected from the App Store for using it. The method below is now the preferred approach. If you need to create several UUID, just use this

How to get a unique device ID in Swift?

由 Deadly 提交于 2019-12-16 22:23:08
问题 How can I get a devices unique ID in Swift? I need an ID to use in the database and as the API-key for my web service in my social app. Something to keep track of this devices daily use and limit its queries to the database. Thanks! 回答1: You can use this (Swift 3): UIDevice.current.identifierForVendor!.uuidString For older versions: UIDevice.currentDevice().identifierForVendor or if you want a string: UIDevice.currentDevice().identifierForVendor!.UUIDString There is no longer a way to

生成Uuid工具类

由 空扰寡人 提交于 2019-12-16 10:23:54
package com.freeter.util;import java.util.UUID;/** * @author liuqi * **/public class Uuid{ public static void getUuid(){ String uuid=UUID.randomUUID().toString().replaceAll("-",""); System.out.println("随机生成Uuid："+uuid); } public static void main(String[] args) { getUuid(); }} 来源： https://www.cnblogs.com/LQ970811/p/12040344.html

VMware vSphere Client数据中心已装载了带有同一UUID

由 只愿长相守 提交于 2019-12-16 08:34:13
主机版本是：ESXi 5.5.0 报错信息：有关此实体的“解析VMFS卷”操作失败，并且提示一下错误消息。 数据中心已装载了带有同一UUID""的VMFS卷。 1、首先登录：ssh登入esxi主机， ~ # esxcli storage vmfs snapshot list #查看未加载的UUID的硬盘 ~ # esxcli storage vmfs snapshot resignature -u 587f213c-5143c130-694b-90b11c33e009 重新加载vmfs的587f213c-5143c130-694b-90b11c33e009卷 ~ # esxcli storage vmfs snapshot resignature -u 587f214a-eba11f24-e7dc-90b11c33e009 重新加载vmfs的587f214a-eba11f24-e7dc-90b11c33e009卷 2、操作之后，回到VMware vSphere Client就可以看得到了。 好了，希望帮到你。 来源： 51CTO 作者： 奋斗者励志 链接： https://blog.51cto.com/chentongsan/2458686

第二周总结

由 ∥☆過路亽．° 提交于 2019-12-15 21:27:02
01.操作系统挂载概念 服务器磁盘如何使用 1) 进行磁盘阵列配置 2) 进行系统分区操作 3) 进行磁盘格式化操作 4) 进入磁盘创建文件系统??? 5) 进行挂载操作使用 ??? 给一个存储设备开个门 如何进行挂载操作: 第一个历程: 挂载环境准备 PS: linux系统中一切皆文件 准备光驱(分区): /dev/cdrom /dev/ 存储设备文件目录 /dev/sda /dev/sda1 /dev/sda2 /dev/sdb /dev/sdc 准备挂载门 : 任意空目录 /mnt 临时挂载点目录 第二个历程: 光驱设备中需要放入光盘 第三个历程: 进行挂载操作 mount 设备文件信息 挂载点目录 mount /dev/cdrom /mnt umount /mnt 第四个历程: 检查确认是否挂载 df --- 检查磁盘信息 02. 系统重要文件数据 /etc目录 1) 网卡配置文件 文件路径信息: /etc/sysconfig/network-scripts/ifcfg-eth0 文件作用说明: 配置网卡地址信息 (IP地址 掩码地址 网关地址 DNS地址信息) 文件详细信息: TYPE=Ethernet --- 指定网络类型 以太网类型 BOOTPROTO=none --- 获取IP地址方式 none static(手动配置地址) dhcp(自动获取地址)

Android and Java Uuid

由 我们两清 提交于 2019-12-14 03:55:21
问题 I want to generate a uuid for my app i tried many things like wifi mac address , getting android id, serial number , creating pseudo uuid from device android.os.Build properties . i also came to know that java itself got Uuid creator class java.util.UUID by going through several articles and blogs i am little confused about this . i want to know that if two android device are creating uuid using this java class( java.util.UUID ) will that be unique or is there any chance for duplication? Also

How can I get the partition UUID of a disk in .NET

由 我的梦境 提交于 2019-12-14 02:13:47
问题 I need to be able to get the partition/filesystem UUID of a partition, similar to how you can with VOL in WinDOS and ls -l /dev/disks/by-partuuid in *nix, but with C# code. What's the best way to do this? For reference, I need to be able to get the UUID from either the current directory, or the "closest" mount upwards. EDIT: My bad, should've said this up front: it needs to run on Mono. 回答1: You can write the code for both platforms and then decide at runtime based on Environment.OSVersion

Time-based UUID (version 1) on iOS?

由 末鹿安然 提交于 2019-12-14 00:35:52
问题 How can we create a RFC 4122 complaint UUID (version 1, time-based) with iOS? 回答1: Here's the man page of the underlying library used by CFUUID and NSUUID . It contains the time based creation function: #include <uuid/uuid.h> uuid_generate_time(uuid_t); It's contained in iOS as well. 来源： https://stackoverflow.com/questions/15501914/time-based-uuid-version-1-on-ios

Hibernate UserType and a defined length

由 限于喜欢 提交于 2019-12-13 16:50:56
问题 I have a hibernate Usertype something like this: public class UUIDHibernateType implements UserType { private static final int[] SQL_TYPES = new int[] { Types.CHAR }; public int[] sqlTypes () { return SQL_TYPES; } // ... } The problem I have is, that hibernate generates a sql script with the types CHAR(1) which is not correct, I would actually need CHAR(36). How would I define the default length of a custom type? For the moment I'm stuck with defining the sql-type like this: <id name="id"

UUID.randomUUID().toString() 的作用

由 旧巷老猫 提交于 2019-12-13 11:28:50
public static String createNewId(){ return UUID.randomUUID().toString() ; } UUID.randomUUID().toString()是javaJDK提供的一个自动生成主键的方法。UUID(Universally Unique Identifier)全局唯一标识符,是指在一台机器上生成的数字，它保证对在同一时空中的所有机器都是唯一的，是由一个十六位的数字组成,表现出来的 形式。由以下几部分的组合：当前日期和时间(UUID的第一个部分与时间有关，如果你在生成一个UUID之后，过几秒又生成一个UUID，则第一个部分不 同，其余相同)，时钟序列，全局唯一的IEEE机器识别号（如果有网卡，从网卡获得，没有网卡以其他方式获得），UUID的唯一缺陷在于生成的结果串会比较长。 来源： CSDN 作者： thunder-1 链接： https://blog.csdn.net/u011582840/article/details/103521691
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