uuid

Read IPhone or iPad UUID using web application

由 天大地大妈咪最大 提交于 2019-12-21 17:31:02
问题 Do you know if is possibile to get the uuid, the result of [[UIDevice currentDevice] uniqueIdentifier], using a web app ? I need to access from iphone/ipad a web page using safari (and not UIwebview under application control) and I should identify the device using its UUID. For example I would like to send an email Message to a user containing a link. When the receiver opens the link from its device I should autenticate him/her through UUID ? Any suggestion ? Thanks Dario 回答1: No this isn't

REST - get a random number GET or POST?

由 痴心易碎 提交于 2019-12-21 09:16:12
问题 How should a random number generator properly be implemented in REST? GET RANDOM/ or.. POST RANDOM/ The server returns a different random number each time. I can see arguments for both ways. 回答1: I'd say this is the same as for a page returned that contains the current time - and many of these are done using GET. Abstractly, fetching a random number (or time) the server's state doesn't change - both time and random numbers can be described as an observation of an external event. E.g. http:/

java中的常用类（二）

由 一笑奈何 提交于 2019-12-21 08:50:32
java中的常用类（二） Math类 Math类的声明: public final class Math extends Object Math类是与数学计算有关的类，里面的方法都是静态方法，直接使用类名来调用即可。 常用方法 以下X表示double,float,int, long abs(X x):求绝对值 max(X x1,X x2):求最大值 min(X x1,X x2)：求最小值 public static double random()：返回带正号的 double 值，该值大于等于 0.0 且小于 1.0。和使用new java.util.Random一样 Math.PI:π的值; public class MathDemo { public static void main(String[] args) { //- abs(X x):求绝对值 // - max(X x1,X x2):求最大值 // - min(X x1,X x2)：求最小值 // - public static double random()：返回带正号的 double 值，该值大于等于 0.0 且小于 1.0。和使用new java.util.Random一样 // - Math.PI:π的值; int abs = Math.abs(-10); System.out.println(abs); int

即时通讯

由 蓝咒 提交于 2019-12-21 08:06:26
前端使用layui框架中的即时通讯 前端的一个代码测试 var uuid,username,head_pic,my_pic,my_name,my_id; apiready = function() { uuid = api.pageParam.uuid; username = api.pageParam.username; if(api.pageParam.head_pic ==''){ head_pic='../../image/moren.png'; }else{ head_pic = localhost+api.pageParam.head_pic; } api.ajax({ url: getUserInfoUrl, method: 'post', }, function(ret, err) { // alert(JSON.stringify(ret)); if(ret){ if(ret.status == 1){ if(ret.result.head_pic){ my_pic = localhost+ret.result.head_pic; }else{ my_pic = "../../image/moren.png" } if(ret.result.resume){ my_name = ret.result.resume.name; }else{ my_name =

How do I find the proper UUID?

由 依然范特西╮ 提交于 2019-12-21 05:40:16
问题 I received help from someone here a week or so ago, but there seems to still be a problem with my code. I am running Android 2.0 so I cannot use the methods to get the UI, instead I need to call the methods reflectively. Below is my code public ConnectThread(BluetoothDevice device, boolean secure) { Log.d(TAG,"here5"); mmDevice = device; BluetoothSocket tmp = null; mSocketType = secure ? "Secure" : "Insecure"; Log.d(TAG,"here6"); // Get a BluetoothSocket for a connection with the // given

Python inverse function of id(…) built-in function

由 倾然丶 夕夏残阳落幕 提交于 2019-12-21 04:49:11
问题 Is there a reverse or inverse of the id built-in function? I was thinking of using it to encode and decode string without taking too much time or having a lot of overhead like the PyCrypto library. The need for me is quite simple so I don't want to use PyCrypto for a simple encode and decode. Something like: >>> id("foobar") 4330174256 >>> reverse_id(4330174256) # some function like this to reverse. "foobar" 回答1: I do not wanna to steal the credits from the man who answered the question This

How to Generate an auto UUID using Hibernate on spring boot

由 倾然丶 夕夏残阳落幕 提交于 2019-12-20 12:34:08
问题 What I am trying to achieve is generate a UUID which is automatically assigned during a DB Insert. Similar to the primary key column named "id" generating an id value. The model values looks something like this: @Id @GeneratedValue(strategy = GenerationType.AUTO) @Column(nullable = false) private Long id; @GeneratedValue(generator = "uuid2") @GenericGenerator(name = "uuid2", strategy = "uuid2") @Column(name = "uuid", columnDefinition = "BINARY(16)") private UUID uuid; But when the DB insert

How do I extract a date from a UUID using Java? [closed]

由 不羁岁月 提交于 2019-12-20 11:57:05
问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 6 years ago . How to convert the UUID to date format 2011-04-22 ? For example, I have UUID like this 118ffe80-466b-11e1-b5a5-5732cf729524. How to convert this to date format? I tried String uuid="118ffe80-466b-11e1-b5a5

Generating a unique ID in PHP

由 允我心安 提交于 2019-12-20 11:56:37
问题 I'm trying to generate a unique ID in php in order to store user-uploaded content on a FS without conflicts. I'm using php, and at the moment this little snippet is responsible for generating the UID: $id = tempnam (".", ""); unlink($id); $id = substr($id, 2); This code is hideous: it creates a temporary file on the FS and deletes it, retaining only the relevant unique part of the generated string. Is there any better way to do this, most preferably without any external dependencies? Thanks

convert uuid to byte, that works when using UUID.nameUUIDFromBytes(b)

由 安稳与你 提交于 2019-12-20 10:24:40
问题 I am converting UUID to byte using this code public byte[] getIdAsByte(UUID uuid) { ByteBuffer bb = ByteBuffer.wrap(new byte[16]); bb.putLong(uuid.getMostSignificantBits()); bb.putLong(uuid.getLeastSignificantBits()); return bb.array(); } However, if I try to recreate the UUID using this function, public UUID frombyte(byte[] b) { return UUID.nameUUIDFromBytes(b); } It is not the same UUID. Converting a randomUUID back and forth returns two different it. UUID u = UUID.randomUUID(); System.out
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