urlencode

Sending arabic characters in URL

◇◆丶佛笑我妖孽 提交于 2019-12-03 16:32:47
i have these arabic sentence: نايتيد أمامه عشرة أيام فقط لكي يقرر مستقبل برباتوف في النادي It must be sent in the url. I tried this approach: $url = 'http://example.com/?q='.urlencode('نايتيد أمامه عشرة أيام فقط لكي يقرر مستقبل برباتوف في النادي'); The result of that encoding is: %D9%86%D8%A7%D9%8A%D8%AA%D9%8A%D8%AF+%D8%A3%D9%85%D8%A7%D9%85%D9%87+%D8%B9%D8%B4%D8%B1%D8%A9+%D8%A3%D9%8A%D8%A7%D9%85+%D9%81%D9%82%D8%B7+%D9%84%D9%83%D9%8A+%D9%8A%D9%82%D8%B1%D8%B1+%D9%85%D8%B3%D8%AA%D9%82%D8%A8%D9%84+%D8%A8%D8%B1%D8%A8%D8%A7%D8%AA%D9%88%D9%81+%D9%81%D9%8A+%D8%A7%D9%84%D9%86%D8%A7%D8%AF%D9%8A But the

Instagram API error 500 UTF-8 hashtags with enforced signature

試著忘記壹切 提交于 2019-12-03 11:17:25
问题 I am receiving 500 error from a simple instagram GET request. My code works when the hashtag contains normal ascii characters, or when my app has the checkbox "Enforce signed requests" unchecked. But I cannot get anything to work when I try with a utf8 hashtag and signed requests enforced. I saw that signed requests will be mandatory soon, so I need it to work. I want to get all images for a tag like #über. public static String signRequest(String key, String data) throws Exception { Mac

How to decode a (doubly) 'url-encoded' string in python

折月煮酒 提交于 2019-12-03 11:00:42
问题 Tried decoding a url-encoded string in the following way some_string = 'FireShot3%2B%25282%2529.png' import urllib res = urllib.unquote(some_string).decode() res u'FireShot3+%282%29.png' Original string is FireShot3 (2).png . Any help would be appreciated. Answer: urllib.unquote_plus(urllib.unquote_plus(some_string)) due to double encoding. 回答1: Your input is encoded double . Using Python 3: urllib.parse.unquote(urllib.parse.unquote(some_string)) Output: 'FireShot3+(2).png' now you have the +

Tastypie with application/x-www-form-urlencoded

匿名 (未验证) 提交于 2019-12-03 08:46:08
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I'm having a bit of difficulty figuring out what my next steps should be. I am using tastypie to create an API for my web application. From another application, specifically ifbyphone.com, I am receiving a POST with no headers that looks something like this: post data:http://myapp.com/api/ callerid=1&someid=2&number=3&result=Answered&phoneid=4 Now, I see in my server logs that this is hitting my server.But tastypie is complaining about the format of the POST. {"error_message": "The format indicated 'application/x-www-form-urlencoded' had no

HttpUtility.UrlEncode in console application

↘锁芯ラ 提交于 2019-12-03 08:17:07
问题 I'd like to use HttpUtility.UrlEncode in a console application, VB.NET, VS 2010 Beta 2. System.Web.HttpUtility.UrlEncode(item) Error message: 'HttpUtility' is not a member of 'Web'. In this question Anjisan suggests to add a reference to System.Web, as follows: In your solution explorer, right click on references Choose "add reference" In the "Add Reference" dialog box, use the .NET tab Scroll down to System.Web, select that, and hit ok However, I don't have a System.Web entry at that

Library to convert JSON to urlencoded

左心房为你撑大大i 提交于 2019-12-03 06:59:24
We are doing some integration towards a quite inconsistent (Zurmo-)REST API. The API only accepts urlencoded strings as its payload in the http posts, but it answers with JSON. So as the documentation was very unclear on this we naturally thought we could post JSON to it, but this was not the case. So now we have all our code generating JSON when we need to send it as x-www-form-urlencoded, is there any java library that can do a conversion from JSON to an urlencoded string? We are currently using the org.json lib, but we can change it if there would be a need for it. Example: This JSON string

06_Fiddler_get请求(url详解)

廉价感情. 提交于 2019-12-03 06:38:12
介绍了Composer的功能,可以模拟get和post请求,get请求有些是不带参数的,这种比较容易,直接放到url地址栏就行。有些get请求会带有参数,本篇详细介绍url地址格式。 一、url详解 1.url就是我们平常打开百度在地址栏输入的:https:www.baidu.com,如下图,这个是最简单的url地址,打开的是百度的主页 2.再看一个稍微复杂一点的url,在百度输入框输入:上海悠悠博客园 3.查看url地址栏,对比之前的百度首页url地址,后面多了很多参数。当然最主要的参数是:wd=上海悠悠博客园(后面的一大串可以暂时忽略)。 4.那么问题来了,这些参数有什么作用呢? 可以做个简单的对比,在地址栏分别输入: https:www.baidu.com https://www.baidu.com/s?wd=上海悠悠博客园 对比打开的页面有什么不一样,现在知道作用了吧,也就是说这个多的"/s?wd=上海悠悠博客园"就是搜索的结果页面 二、url解析 1.以"https://www.baidu.com/s?wd=上海悠悠博客园"这个url请求的抓包为例 2.那么一个完整的url地址,基本格式如下: https://host:port/path?xxx=aaa&ooo=bbb --http/https:这个是协议类型,如图中1所示 --host:服务器的IP地址或者域名

How to know if a URL is decoded/encoded?

好久不见. 提交于 2019-12-03 05:52:24
I am using Javascript method decodeURIComponent to decode an encoded URL. Now I am having an issue, that sometimes the URL is get encoded twice during redirection between servers, sometimes it is encoded only once. I want to check that if the URL is still encoded after calling the method decodeURIComponent . How can I do that? Any pointer would be very helpful to me. Update - 1 If I recursively call a method and check that if the given URL still contains "%", if it contains "%" then decode it and call the method again; and if not return it to the caller, will that work? Update - 2 For my case

Do colons require encoding in URI query parameters?

老子叫甜甜 提交于 2019-12-03 05:50:51
I've noticed that Java's UriBuilder isn't encoding the : characters included in my query parameter values (ISO 8601-formatted strings). According to Wikipedia, it seems colon should be encoded. In particular, encoding the query string uses the following rules: Letters (A-Z and a-z), numbers (0-9) and the characters '.','-','~' and '_' are left as-is SPACE is encoded as '+' or %20[citation needed] All other characters are encoded as %FF hex representation with any non-ASCII characters first encoded as UTF-8 (or other specified encoding) So, what's the deal? Should colons in query parameters be

How to URL encode in Python 3?

拟墨画扇 提交于 2019-12-03 05:30:19
问题 I have tried to follow the documentation but was not able to use urlparse.parse.quote_plus() in Python 3 : from urllib.parse import urlparse params = urlparse.parse.quote_plus({'username': 'administrator', 'password': 'xyz'}) I get AttributeError: 'function' object has no attribute 'parse' 回答1: You misread the documentation. You need to do two things: Quote each key and value from your dictionary, and Encode those into a URL Luckily urllib.parse.urlencode does both those things in a single