upload

Google AppEngine Python Web upload file and read the content

本小妞迷上赌 提交于 2020-01-25 04:53:27
问题 I'm new at Python AND AppEngine, so maybe my question is basic but I've searched it for hours... So, I'm using Google AppEngine with python and HTML... So in my htlm file I have something like that : <form action="/sign?guestbook_name={{ guestbook_name }}" method="post"> <div><input type="file" name="file"></div> <div><textarea name="content" rows="3" cols="60"></textarea></div> <div><input type="submit" value="Sign Guestbook"></div> </form> and in my py file, something like that : class

Upload / Naming folders to a destination folder on Google Drive using Google Apps Script

元气小坏坏 提交于 2020-01-24 20:56:11
问题 My skills in coding/scripting are limited, please bear with me on incorrect terminologies; I need people to input three values on the form, [Objectives, Goals, and Remarks] followed by uploading an attachment (s) to my Google Drive. The script that I found (attached below) is working but needs to be adjusted (edited) for my needs. Please, I need help with the following: Right now, the files when uploaded, proceed to the default Google Drive folder. But I need them to be directed to a folder

Don't allow > 2mb images

試著忘記壹切 提交于 2020-01-24 13:45:13
问题 HI! How do i check if the users are trying to upload bigger than 2mb files? I would like to deny that and put an error message to the user who is trying to do that. I know it is something like this, but what shall i change the 50000 to to become 2mb? if ($_FILES['imagefile']['size'] > 50000 ) { die ("ERROR: Large File Size"); } 回答1: 2 MB is 2097152 bytes. Change the 50000 to 2097152 and you're set. 回答2: The 5,000 is the number of byes, so basically you just need to convert 2MB to bytes. 1 MB

Don't allow > 2mb images

烈酒焚心 提交于 2020-01-24 13:44:24
问题 HI! How do i check if the users are trying to upload bigger than 2mb files? I would like to deny that and put an error message to the user who is trying to do that. I know it is something like this, but what shall i change the 50000 to to become 2mb? if ($_FILES['imagefile']['size'] > 50000 ) { die ("ERROR: Large File Size"); } 回答1: 2 MB is 2097152 bytes. Change the 50000 to 2097152 and you're set. 回答2: The 5,000 is the number of byes, so basically you just need to convert 2MB to bytes. 1 MB

Image upload, ajax, php, mysql

爱⌒轻易说出口 提交于 2020-01-23 17:59:11
问题 I have one question. Is possible upload image from file input to MySQL with Ajax POST and PHP? Like this: <script type="text/javascript"> $(document).ready(function(){ $("button").click(function(){ $("#form_id").submit(function(){ $.ajax({ type:"POST", data:image_data, url:"/path_to_php/ImageSave.php", success: function(msg){ alert("ok"); } }); return false; }); }); }); </script> <form name="form_name" id="form_id" action="#" method="POST"> <input type="file" name="image" id="image" />

why tmp_name is used in this example

怎甘沉沦 提交于 2020-01-23 12:51:11
问题 I am quite new to php.I was going through an example on file uploading.Here inside getimagesize() function $_FILES['file']['temp_name'] is used.and when i echoed $_FILES['file']['temp_name'] it shows the following output: C:\xampp\tmp\phpDE4B.tmp my questions are: 1.why use tmp_name instead of original name inside getimagesize() function. 2.For what reason this tmp_name is created ? 3.How it is generated? $target_dir = "uploads/"; $target_file = $target_dir . basename($_FILES["fileToUpload"][

why tmp_name is used in this example

℡╲_俬逩灬. 提交于 2020-01-23 12:51:03
问题 I am quite new to php.I was going through an example on file uploading.Here inside getimagesize() function $_FILES['file']['temp_name'] is used.and when i echoed $_FILES['file']['temp_name'] it shows the following output: C:\xampp\tmp\phpDE4B.tmp my questions are: 1.why use tmp_name instead of original name inside getimagesize() function. 2.For what reason this tmp_name is created ? 3.How it is generated? $target_dir = "uploads/"; $target_file = $target_dir . basename($_FILES["fileToUpload"][

What is the right way to post image to REST API and gather data with Falcon library?

雨燕双飞 提交于 2020-01-23 12:25:10
问题 I try to post an image to process it through my REST API. I use falcon for the backend but could not figure out how to post and receive the data. This is how I currently send my file img = open('img.png', 'rb') r = requests.post("http://localhost:8000/rec", files={'file':img}, data = {'apikey' : 'bla'}) However at the Falcon repo they say that Falcon does not support HTML forms to send data instead it aims full scope of POSTed and PUTed data which I do not differentiate POSTed image data and

File Upload Error in MediaWiki 1.22.3 - Could not create directory “mwstore://local-backend/local-public/7/70”

被刻印的时光 ゝ 提交于 2020-01-23 07:23:35
问题 We recently upgraded our MediaWiki installation to 1.22.3 running on Ubuntu 12.04.2 LTS. Now when we try to upload files, we get the following error: Could not create directory "mwstore://local-backend/local-public/7/70" 回答1: Finally found the solution in the MediaWiki documentation. The problem was the ownership of the images directory. Making the adjustments suggested in the documentation eliminated the problem. See the following for details: http://www.mediawiki.org/wiki/Manual:Configuring

File Upload Error in MediaWiki 1.22.3 - Could not create directory “mwstore://local-backend/local-public/7/70”

房东的猫 提交于 2020-01-23 07:22:47
问题 We recently upgraded our MediaWiki installation to 1.22.3 running on Ubuntu 12.04.2 LTS. Now when we try to upload files, we get the following error: Could not create directory "mwstore://local-backend/local-public/7/70" 回答1: Finally found the solution in the MediaWiki documentation. The problem was the ownership of the images directory. Making the adjustments suggested in the documentation eliminated the problem. See the following for details: http://www.mediawiki.org/wiki/Manual:Configuring